我正在尝试提交带有codeigniter的表单,当我提交表单时,请获取一个空白页面。我哪里出错?
查看
echo "<form class='order_ctn_parent' method='POST' action='add/insert_orders'>";
//inputs
echo "</form>";
控制器
class Add extends CI_Controller {
public function __construct()
{
parent::__construct();
}
public function index() {
}
public function insert_orders()
{
$this->load->model('order_model', 'order');
$this->order->insert_orders();
redirect('view_orders', 'location');
}
}
模型
class Order_model extends CI_Model {
public function insert_orders()
{
$DB2 = $this->load->database('orders', TRUE);
$timber_array = $this->input->post("timber_choose");
$products_array = $this->input->post("product_choose");
$qty_array = $this->input->post("quantity");
$price_array = $this->input->post("price");
$qty_array = $this->input->post("quantity");
$loop = 0;
foreach($products_array as $product) {
$price = str_replace("£","",$price_array[$loop]);
$data = array(
'product_code' => "",
'timber_type' => $timber_array[$loop],
'product' => $product,
'quantity' => $qty_array[$loop],
'price' => $price
);
$DB2->insert('timber_order_products', $data);
$loop++;
}
}
}
答案 0 :(得分:1)
尝试这样的事情
?>//end of php
<form class='order_ctn_parent' method='POST' action='<?php echo base_url()?>add/insert_orders'>
</form>
并在__construct()
中加载模型,就像这样
public function __construct()
{
parent::__construct();
$this->load->model('order_model', 'order');
}
,无需检查$DB2 = $this->load->database('orders', TRUE);
和Codeigniter插入应为Like This
答案 1 :(得分:0)
提交后请检查您的网址。我相信你的表格行动不起作用。将适当的控制器及其功能url提供给Form动作。例子就在这里。
<?php echo site_url('add/insert_orders);?>
其中add将是您的控制器,insert_orders将是添加控制器的功能。