Question

通过使用Twilio（VideoCallKitQuickStart）提供的示例视频通话应用程序之一，我试图通过向应用程序发送VoIP通知来触发来电。但该应用程序不会触发来电。我还尝试通过抛出以下异常

，在发送VoIP通知和应用程序崩溃时保持应用程序打开

NSInvalidArgumentException：尝试插入非属性列表对象＆＃39; PKPushPayload：0x16e44af0＆＃39;为了钥匙有效载荷

当有人收到VoIP通知时，有人可以帮助我或指导我如何在应用程序中触发来电。

以下是我在ViewController.swift文件中的代码

 func pushRegistry(registry: PKPushRegistry!, didReceiveIncomingPushWithPayload payload: PKPushPayload!, forType type: String!) {
        // Process the received push

        self.reportIncomingCall(uuid: UUID(), roomName: "testRoom", completion: nil)
    } 

func reportIncomingCall(uuid: UUID, roomName: String?, completion: ((NSError?) -> Void)? = nil) {

    let callHandle = CXHandle(type: .generic, value: roomName ?? "")
    let callUpdate = CXCallUpdate()
    callUpdate.remoteHandle = callHandle
    callUpdate.supportsDTMF = false
    callUpdate.supportsHolding = true
    callUpdate.supportsGrouping = false
    callUpdate.supportsUngrouping = false
    callUpdate.hasVideo = true

    callKitProvider.reportNewIncomingCall(with: uuid, update: callUpdate) { error in
        if error == nil {
            NSLog("Incoming call successfully reported.")
        } else {
            NSLog("Failed to report incoming call successfully: \(error?.localizedDescription).")
        }
        completion?(error as? NSError)
    }
}

Answer 1

发布较晚的答案，但可能对某人有帮助。

以下是我处理语音来电的代码。

func pushRegistry(_ registry: PKPushRegistry, didReceiveIncomingPushWith payload: PKPushPayload, for type: PKPushType) {
    NSLog("pushRegistry:didReceiveIncomingPushWithPayload:forType:")
    print(payload)
    if (type == PKPushType.voIP) {
        TwilioVoice.handleNotification(payload.dictionaryPayload, delegate: self)

        pushKitPushReceivedWithPayload(payload: payload)
    }
}
func pushRegistry(_ registry: PKPushRegistry, didReceiveIncomingPushWith payload: PKPushPayload, for type: PKPushType, completion: @escaping () -> Void) {
    NSLog("pushRegistry:didReceiveIncomingPushWithPayload:forType:completion:")

    if (type == PKPushType.voIP) {
        TwilioVoice.handleNotification(payload.dictionaryPayload, delegate: self)

        pushKitPushReceivedWithPayload(payload: payload)
    }

    completion()
}

func pushKitPushReceivedWithPayload(payload: PKPushPayload){
    if UIApplication.shared.applicationState != .active{
        let msgType = payload.dictionaryPayload["twi_message_type"] as? String
        if let messageType = msgType{
            if messageType == "twilio.voice.call"{
                fireLocalNotificationForVoiceCall(didStart: true)
            }else if messageType == "twilio.voice.cancel"{
                fireLocalNotificationForVoiceCall(didStart: false)
            }
        }
    }
}

下面是我添加的呼叫工具包的委托方法

extension AppDelegate : TVONotificationDelegate, TVOCallDelegate
{
  func callInviteReceived(_ callInvite: TVOCallInvite) 
  {
   if (callInvite.state == .pending) 
   {
        //code
   } 
   else if (callInvite.state == .canceled) 
   {
        //code
   }
  }
  func handleCallInviteReceived(_ callInvite: TVOCallInvite) 
  {
        //code
  }

  func handleCallInviteCanceled(_ callInvite: TVOCallInvite) 
  {
        //code
  }
}

我已遵循twilio提供的本教程-https://github.com/twilio/voice-quickstart-swift

阅读本教程，它将起作用。

Answer 2

Twilio开发者传道者在这里。

我对iOS不是特别擅长，但要快速查看PKPushRegistryDelegate的文档，看起来您的pushRegistry函数定义是对的。

应该是

func pushRegistry(_ registry: PKPushRegistry, 
    didReceiveIncomingPushWith payload: PKPushPayload, 
    forType type: PKPushType)

即didReceiveIncomingPushWith而不是didReceiveIncomingPushWithPayload。

或者，它是否与您将forType投放到String这一事实有关？

Answer 3

Swift 3.0

border-inline-end

请不要对有效负载进行任何更改而不进行修改，以便SDK从有效负载中提取来电信息，以便SDK可以通过来电通知应用程序

使用CallKit和Twilio-Video API触发传入的VoIP呼叫

3 个答案: