Question

我希望有一个查询累加在一个列上，但它需要每个星期一重新启动但看起来不可能用窗口函数来实现这是我的代码：

    WITH t  (fecha, nombre_dia, distribuidor, monto)as (
SELECT CAST(t.fecha AS DATE)fecha
, CASE WHEN datename(dw,t.fecha)='Monday' then 1 else 2 end  nombre_dia
,d.NombreDistribuidor distribuidor
,sum(tr.Monto)monto

from HechosTransferencia tr inner join DimensionTiempo t on tr.DimensionTiempoId=t.DimensionTiempoId
inner join DimensionDistribuidor d on d.DimensionDistribuidorId=tr.DimensionDistribuidorId
WHERE        (t.Fecha BETWEEN DATEADD(MONTH, DATEDIFF(MONTH, - 2, GETDATE()) - 2, 0) AND GETDATE())
group by CAST(t.fecha AS DATE)
, CASE WHEN datename(dw,t.fecha)='Monday' then 1 else 2 end ,d.NombreDistribuidor
)SELECT *, 
SUM(monto) OVER(PARTITION BY nombre_dia, distribuidor
                ORDER BY fecha, nombre_dia, distribuidor  ROWS UNBOUNDED PRECEDING) AS RunningTotal
 from t where distribuidor='XYZ'

一个简单的输出样本将是

monday           XYZ    5      5
tuesday          XYZ    1      6
wednesday        XYZ    2      8
..
....
monday           XYZ    2       2         -- restart value every monday
tuesday          XYZ    2       4
..
...

Answer 1

我刚刚在rextester中设置了一个示例：http://rextester.com/MEXHM63945

不要试图在每个星期一打破累积金额，只需将星期一设置为星期的第一天，而将SUM（）设置为提供者和WeekOfMonth。

我还没有测试过，但我认为你可以在不使用CTE窗口功能的情况下获得它。（看看答案的结尾。）

-- Set monday first day of week
SET DATEFIRST 1;

create table #data ([date] datetime, provider varchar(10), value int);
insert into #data values
('2017-01-02', 'XYZ', 1),
('2017-01-03', 'XYZ', 5),
('2017-01-04', 'XYZ', 3),
('2017-01-05', 'XYZ', 5),
('2017-01-06', 'XYZ', 4),
('2017-01-07', 'XYZ', 11),
('2017-01-08', 'XYZ', 11),
('2017-01-09', 'XYZ', 1),
('2017-01-10', 'XYZ', 5),
('2017-01-11', 'XYZ', 3),
('2017-01-12', 'XYZ', 5),
('2017-01-13', 'XYZ', 4),
('2017-01-14', 'XYZ', 11),
('2017-01-15', 'XYZ', 11);


SELECT provider, DATEPART(WEEK, date) as week_of_year, value,  
       sum(value) OVER (Partition by provider, DATEPART(WEEK, date) ORDER BY date, provider) Acm
FROM #data
ORDER BY date, provider;

结果如下：

+----------+--------------+-------+-----+
| provider | week_of_year | value | Acm |
+----------+--------------+-------+-----+
|    XYZ   |       2      |   1   |  1  |
+----------+--------------+-------+-----+
|    XYZ   |       2      |   5   |  6  |
+----------+--------------+-------+-----+
|    XYZ   |       2      |   3   |  9  |
+----------+--------------+-------+-----+
|    XYZ   |       2      |   5   |  14 |
+----------+--------------+-------+-----+
|    XYZ   |       2      |   4   |  18 |
+----------+--------------+-------+-----+
|    XYZ   |       2      |   11  |  29 |
+----------+--------------+-------+-----+
|    XYZ   |       2      |   11  |  40 |
+----------+--------------+-------+-----+
|    XYZ   |       3      |   1   |  1  |
+----------+--------------+-------+-----+
|    XYZ   |       3      |   5   |  6  |
+----------+--------------+-------+-----+
|    XYZ   |       3      |   3   |  9  |
+----------+--------------+-------+-----+
|    XYZ   |       3      |   5   |  14 |
+----------+--------------+-------+-----+
|    XYZ   |       3      |   4   |  18 |
+----------+--------------+-------+-----+
|    XYZ   |       3      |   11  |  29 |
+----------+--------------+-------+-----+
|    XYZ   |       3      |   11  |  40 |
+----------+--------------+-------+-----+

我认为这应该可以胜任：

SELECT 
    CAST(t.fecha AS DATE) fecha
    , d.NombreDistribuidor distribuidor
    , SUM(tr.Monto) OVER (PARTITION BY d.NombreDistribuidor, DATEPART(week, CAST(t.fecha AS DATE))
                          ORDER BY CAST(t.fecha AS DATE), d.NombreDistribuidor) monto
FROM 
    HechosTransferencia tr 
    INNER JOIN DimensionTiempo t ON tr.DimensionTiempoId=t.DimensionTiempoId
    INNER JOIN DimensionDistribuidor d ON d.DimensionDistribuidorId=tr.DimensionDistribuidorId
WHERE        
    (t.Fecha BETWEEN DATEADD(MONTH, DATEDIFF(MONTH, - 2, GETDATE()) - 2, 0) AND GETDATE())
GROUP BY 
    CAST(t.fecha AS DATE), d.NombreDistribuidor;

Answer 2

根据McNets提出的解决方案，我的问题的答案是：

SET DATEFIRST 1;

WITH t  (fecha, distribuidor, monto)as (
SELECT CAST(t.fecha AS DATE)fecha
,d.NombreDistribuidor distribuidor
,sum(tr.Monto)monto
 from HechosTransferencia tr inner join DimensionTiempo t on tr.DimensionTiempoId=t.DimensionTiempoId
inner join DimensionDistribuidor d on d.DimensionDistribuidorId=tr.DimensionDistribuidorId
WHERE        (t.Fecha BETWEEN DATEADD(MONTH, DATEDIFF(MONTH, - 2, GETDATE()) - 2, 0) AND GETDATE())
group by CAST(t.fecha AS DATE)
,d.NombreDistribuidor
)SELECT *
,sum(monto) OVER (Partition by distribuidor, DATEPART(WEEK, fecha) ORDER BY fecha, distribuidor)RunningTotal

 from t;

星期一的TSQL窗口函数

2 个答案: