实施例：
$startDate是2007-02-05星期一，$endDate是2007-02-20星期二。然后我希望它列出：
Monday 2007-02-05
Monday 2007-02-12
Monday 2007-02-19
我查看了PHP手册，发现这是为了获得两个日期之间的所有日子。但是如何以我想要的方式做到这一点？ PHP代码：
答案 0 :(得分：38)
不是让所有日子都循环通过它们，而是在开始日期之后获得第一个星期一，然后一次迭代7天：
$endDate = strtotime($endDate);
for($i = strtotime('Monday', strtotime($startDate)); $i <= $endDate; $i = strtotime('+1 week', $i))
echo date('l Y-m-d', $i);
答案 1 :(得分：7)
我需要相同并创建一个简单的方法。
public function getMondaysInRange($dateFromString, $dateToString)
{
$dateFrom = new \DateTime($dateFromString);
$dateTo = new \DateTime($dateToString);
$dates = [];
if ($dateFrom > $dateTo) {
return $dates;
}
if (1 != $dateFrom->format('N')) {
$dateFrom->modify('next monday');
}
while ($dateFrom <= $dateTo) {
$dates[] = $dateFrom->format('Y-m-d');
$dateFrom->modify('+1 week');
}
return $dates;
}
然后使用它。
$dateFromString = '2007-02-05';
$dateToString = '2007-02-20';
var_dump($this->getMondaysInRange($dateFromString, $dateToString));
结果：
array (size=3)
0 => string '2007-02-05' (length=10)
1 => string '2007-02-12' (length=10)
2 => string '2007-02-19' (length=10)
也许这会对某人有所帮助。
答案 2 :(得分：6)
您可以使用以下函数获取特定日期的日期范围之间的日期数组。
您必须输入开始日期，结束日期和日期编号。日期编号如下。 1 =星期一，2 =星期二，3 =星期三，4 =星期四。 5 =星期五，6 =星期六，7 =星期天。
function getDateForSpecificDayBetweenDates($startDate,$endDate,$day_number){
$endDate = strtotime($endDate);
$days=array('1'=>'Monday','2' => 'Tuesday','3' => 'Wednesday','4'=>'Thursday','5' =>'Friday','6' => 'Saturday','7'=>'Sunday');
for($i = strtotime($days[$day_number], strtotime($startDate)); $i <= $endDate; $i = strtotime('+1 week', $i))
$date_array[]=date('Y-m-d',$i);
return $date_array;
}
答案 3 :(得分：3)
for ($i = strtotime($startDate); $i <= strtotime($endDate); $i = strtotime('+1 day', $i)) {
if (date('N', $i) == 1) //Monday == 1
echo date('l Y-m-d', $i); //prints the date only if it's a Monday
}
答案 4 :(得分：2)
我创建一个课程，你可以获得所有天数范围日期组按天名：
class DayHelper{
const MONDAY = 'Mon';
const TUESDAY = 'Tue';
const WEDENSDAY = 'Wed';
const THURSDAY = 'Thu';
const FRIDAY = 'Fri';
const SATURDAY = 'Sat';
const SUNDAY = 'Sun';
public function GetYeardays($dateStart, $dateend){
$period = new \DatePeriod(
new \DateTime($dateStart), new \DateInterval('P1D'), (new \DateTime($dateend))
);
$dates = iterator_to_array($period);
$arrayreturn = array();
foreach ($dates as $val) {
$date = $val->format('Y-m-d'); //format date
$get_name = date('l', strtotime($date)); //get week day
$day_name = substr($get_name, 0, 3); // Trim day name to 3 chars
switch ($day_name) {
case self::MONDAY:
$MONDAY[] = $date;
$arrayreturn[self::MONDAY] = $MONDAY;
break;
case self::TUESDAY:
$TUESDAY[] = $date;
$arrayreturn[self::TUESDAY] = $TUESDAY;
break;
case self::WEDENSDAY:
$WEDENSDAY[] = $date;
$arrayreturn[self::WEDENSDAY] = $WEDENSDAY;
break;
case self::THURSDAY:
$THURSDAY[] = $date;
$arrayreturn[self::THURSDAY] = $THURSDAY;
break;
case self::FRIDAY:
$FRIDAY[] = $date;
$arrayreturn[self::FRIDAY] = $FRIDAY;
break;
case self::SATURDAY:
$SATURDAY[] = $date;
$arrayreturn[self::SATURDAY] = $SATURDAY;
break;
case self::SUNDAY:
$SUNDAY[] = $date;
$arrayreturn[self::SUNDAY] = $SUNDAY;
break;
}
}
return $arrayreturn;
}
}
输出将是这样的
array (size=7)
'Fri' =>
array (size=5)
0 => string '2016/01/01' (length=10)
1 => string '2016/01/08' (length=10)
2 => string '2016/01/15' (length=10)
3 => string '2016/01/22' (length=10)
4 => string '2016/01/29' (length=10)
'Sat' =>
array (size=5)
0 => string '2016/01/02' (length=10)
1 => string '2016/01/09' (length=10)
2 => string '2016/01/16' (length=10)
3 => string '2016/01/23' (length=10)
4 => string '2016/01/30' (length=10)
'Sun' =>
array (size=4)
0 => string '2016/01/03' (length=10)
1 => string '2016/01/10' (length=10)
2 => string '2016/01/17' (length=10)
3 => string '2016/01/24' (length=10)
'Mon' =>
array (size=4)
0 => string '2016/01/04' (length=10)
1 => string '2016/01/11' (length=10)
2 => string '2016/01/18' (length=10)
3 => string '2016/01/25' (length=10)
'Tue' =>
array (size=4)
0 => string '2016/01/05' (length=10)
1 => string '2016/01/12' (length=10)
2 => string '2016/01/19' (length=10)
3 => string '2016/01/26' (length=10)
'Wed' =>
array (size=4)
0 => string '2016/01/06' (length=10)
1 => string '2016/01/13' (length=10)
2 => string '2016/01/20' (length=10)
3 => string '2016/01/27' (length=10)
'Thu' =>
array (size=4)
0 => string '2016/01/07' (length=10)
1 => string '2016/01/14' (length=10)
2 => string '2016/01/21' (length=10)
3 => string '2016/01/28' (length=10)
答案 5 :(得分：1)
这是获取＆＃34; $ startdate＆＃34;的工作日的代码。并计算两个日期之间的工作日数。
`$startdate` = '2015-03-01';
`$endate` = '2015-03-31';
`$recurringDay` = date('N', strtotime($startdate)); // recurring Day from date i.e monday = 1, Tuesday = 2 ...etc
$begin = new DateTime(`$startdate`);
$end = new DateTime(date('Y-m-d',strtotime('+1 day', strtotime($endate))));
while($begin format('Y-m-d');
$day[] = $begin->format('N');
$begin->modify('+1 day');
}
$c=0; // counter starts
foreach($day as $key=>$dt) {
if ($dt==`$recurringDay`) // compare it
{
$k[] = $key;
$c++;
}
}
`$nofDays` = $c; // number of mondays , tuesday
foreach($k as $pp) {
//adding session code
`$recurringDatetime[]` = $period[$pp]; // recurring dates
}
print_r(`$recurringDatetime`); // array of dates of monday, tuesday ..etc
答案 6 :(得分：1)
$dates = array();
$dates[] = strtotime($start);
for($i = 0; $i <= 12; $i++){
$dates[] = strtotime('+1 week', $dates[$i]);
}
foreach($dates as $date){ echo date("d.m.Y", $date); }
我有类似的问题，课程可以在任何一天开始。这个脚本选择开始日并每周收集下一天，直到想要的金额（在这种情况下为12）。
答案 7 :(得分：0)
在此之前将$ startDate和$ endDate转换为时间戳：
foreach ($date = $startDate; $date <= $endDate; $date += 60 * 60 * 24) {
if (strftime('%w', $date) == 1) {
$mondays[] = strftime('%A %Y-%m-%d', $date);
}
}
答案 8 :(得分：0)
只需添加为，
padding:0答案 9 :(得分：0)
我对响应https://stackoverflow.com/a/37300272/6871295
进行了一些更改然后我可以获取任意一天的日期之间的日期并返回格式。
public function getWeekDayInRange($weekday, $dateFromString, $dateToString, $format = 'Y-m-d')
{
$dateFrom = new \DateTime($dateFromString);
$dateTo = new \DateTime($dateToString);
$dates = [];
if ($dateFrom > $dateTo) {
return $dates;
}
if (date('N', strtotime($weekday)) != $dateFrom->format('N')) {
$dateFrom->modify("next $weekday");
}
while ($dateFrom <= $dateTo) {
$dates[] = $dateFrom->format($format);
$dateFrom->modify('+1 week');
}
return $dates;
}