Question

当我运行以下代码时，我得到一个错误，说“列表索引必须是整数，而不是元组”。当我声明第一个和第二个变量时，会出现此错误。任何人都可以解释或修复此错误

    globalViewDict = {'A': [('B', 6.5, 5001), ('F', 2.2, 5005), 'A', '2'], 
                  'B': [('A', 6.5, 5000), ('C', 1.1, 5002), ('D', 4.2, 5003), ('E', 3.2, 5004), 'B', '4'],
                  'C': [('B', 1.1, 5001), ('D', 1.6, 5003), 'C', '2'],
                  'D': [('F', 0.7, 5005), ('B', 4.2, 5001), ('C', 1.6, 5002), ('E', 2.9, 5004), 'D', '4'],
                  'E': [('B', 3.2, 5001), ('D', 0.7, 5003), ('F', 6.2, 5005), 'E', '3'],
                  'F': [('A', 2.2, 5000), ('D', 0.7, 5003), ('E', 6.2, 5004),'F','3']}

def dijkstrawPhase():
    global globalViewDict
    pprint.pprint(globalViewDict)
    #print "globalViewDict:", globalViewDict
    print""
    tempList =[]
    temptup = ()
    newList = []
    x=0

    for key,value in globalViewDict.iteritems():
        x=0
        i=0
        neighborsOfPacket = int(value[-1])
        while x < neighborsOfPacket:
            j=0
            id = str(value[i][0])
            cost = float(value[i][1])
            temptup =(key,id,cost)
            i = i + 1
            x = x + 1
            tempList.append(temptup)
    print "tempList\n",pprint.pprint(tempList)


    for x in tempList:
        first = tempList[x][0]
        second = tempList[x][1]
        j=0
        for j in tempList:
            if tempList[j][0]==second and tempList[j][i] == first:
                print "nothng dne"
            else:
                newList.append(tempList[x])
    print "newList\n",pprint.pprint(newList)

dijkstrawPhase()

Answer 1

在顶部的for循环中，您可以向tempList添加一些元组。

 temptup =(key,id,cost)
 tempList.append(temptup)

在底部循环中，您可以：

for x in tempList:
    first = tempList[x][0]
    second = tempList[x][1]

x指的是列表中的项目 - 元组，而不是索引。你想要的更像是这样：

for x in tempList:
    first = x[0]
    second = x[1]

“列表索引必须是整数，而不是元组”

1 个答案: