Question

任何人都可以查看我的代码并告诉我为什么电子邮件没有发送？我正在尝试编写一个jQuery Ajax方法，将联系表单数据发布到PHP电子邮件脚本。

以下是联系表单页面的正文：

<body>
    <?php require 'Includes/Header.php' ?>
<div id="container1">
    <h1>Contact Us</h1> 
    <form id="form" onSubmit="return validate(this);" method="post" action="customerMsg2.php" >
    <table>
        <tr>
            <td>First Name: </td>
            <td><input type="text" name="FirstName" id="FirstName" autofocus></td>
        </tr>
        <tr>
            <td>Last Name: </td>
            <td><input type="text" name="LastName" id="LastName"></td>
        </tr>
        <tr>
            <td>Email: </td>
            <td><input type="text" name="Email" id="Email"></td>
        </tr>
        <tr>
            <td>Leave a message: </td>
            <td><textarea name="Message" id="Message"></textarea></td>
        </tr>
        <tr>
            <td><input type="submit" id="sendEmail" value="Send Email"></td>
        </tr>
        <input type="hidden" name="submitted" value="true">
    </table>
    </form>
    <div id="ajax-message"></div>
</div>
<div id="container2">
    <ul id="slideshow">
        <li id="services"><h2>Make a Donation!</h2><br>
            Our pets need lots of love and attention while they wait for new homes.  Why not give today?<br><input type="button" value="Donate"></li>
        <li id="services"><h2>Check Out Our Podcast!</h2><br>
            Tune in weekly as Josh gives his unique perspective on pet-ownership and dutifully regulated capitalism.</li>
    </ul>
</div>
    <script src="slideshow.js"></script>
    <script src="ajaxsubmit.js"></script>
    <?php require 'Includes/Footer.php' ?>
</body>
</html>

这是jQuery，ajax代码（ajaxsubmit.js）：

$(document).ready(function () {
    var $form = $('#form');
    var ajaxmessage = $('#ajax-message');

    $form.submit(function (event) {
        event.preventDefault();
        var serializedData = $form.serialize();
        $.ajax({
            type: 'POST',
            url: $form.attr('action'),
            data: serializedData
        })
            .done(function (response) {
                $(ajaxmessage).removeClass('error');
                $(ajaxmessage).addClass('success');
                $(ajaxmessage).text(response);

                $('#FirstName').val('');
                $('#LastName').val('');
                $('#Email').val('');
                $('#Message').val('');
            })
            .fail(function (data) {
                $(ajaxmessage).removeClass('success');
                $(ajaxmessage).addClass('error');
                if (data.responseText !== '') {
                    $(ajaxmessage).text(data.responseText);
                } else {
                    $(ajaxmessage).text('Oops! An error occured and your message could not be sent.');
                }
            });
    });
});

这是PHP脚本：

<?php 

        ini_set('SMTP', 'smtp.gmail.com');
        $to = '(i would put my email address here)';
        $firstname = strip_tags(trim($_POST["FirstName"]));
        $lastname = strip_tags(trim($_POST["LastName"]));
        $message = trim($_POST["Message"]);    
        $from = trim($_POST['Email']);
        $subject = "New contact from $firstname $lastname";


        if(mail($to, $subject, $message, $from))
        {
            echo "Message sent.";
        }
        else
        {
            echo "Message not sent.";
        }

?>

有什么想法吗？

Answer 1

这是来自php doc的一个例子：

`<?php
   $to      = 'nobody@example.com';
  $subject = 'the subject';
  $message = 'hello';
  $headers = 'From: webmaster@example.com' . "\r\n" .
  'Reply-To: webmaster@example.com' . "\r\n" .
  'X-Mailer: PHP/' . phpversion();
  mail($to, $subject, $message, $headers);
?>

您的标题信息不正确。
再见

Answer 2

我没有检查你的所有代码，但PHP脚本有几个问题：

首先，邮件功能定义如下：

bool mail ( string $to , string $subject , string $message [, string $additional_headers [, string $additional_parameters ]] )

您不能只将电子邮件地址字符串设为$additional_headers。

例如：

$header = "From: " . $from . "\r\n";
mail($to, $subject, $message, $header);

此外，我猜您不能通过gmail服务器发送带有不同标题的电子邮件作为您的电子邮件地址。通常，您的托管服务提供商已经配置了使用php邮件功能发送电子邮件所需的设置。

尝试编写将联系表单数据发布到PHP电子邮件脚本的jQuery Ajax方法

2 个答案: