Question

我编写了以下功能，可根据搜索查询搜索用户：

        public function search_quick($query) {
        global $db, $system;
        $results = array();

        $person = $db->query(sprintf("SELECT * FROM users WHERE user_id = %s AND user_token = %s", secure($_COOKIE[$this->_cookie_user_id], 'int'), secure($_COOKIE[$this->_cookie_user_token]) )) or _error(SQL_ERROR_THROWEN);
            if($person->num_rows > 0) {
                $this->_data = $person->fetch_assoc();
            }

        $user_id = $this->_data['user_id'];
        $latitude = $this->_data['latitude'];
        $longitude = $this->_data['longitude']; 
        $user_gender = $this->_data['user_gender'];
        $user_sex = $this->_data['user_sex'];
        $sexual_preference = $this->_data['sexual_preference'];
        $sexual_orientation = $this->_data['sexual_orientation'];
        $age_range = explode(',',$this->_data['age_range']);
        $distance_range = explode(',',$this->_data['distance_range']);


        $people = $db->query(sprintf('SELECT * FROM users WHERE user_fullname LIKE %1$s LIMIT %2$s', secure($query, 'search'), secure($system['min_results'], 'int', false) )) or _error(SQL_ERROR_THROWEN);

    $get_users = $db->query(sprintf('
    SELECT *,
    3956 * 2 * ASIN(SQRT( POWER(SIN((%s - latitude) * pi()/180 / 2), 2) + COS(%s * pi()/180) * COS(latitude * pi()/180) *
    POWER(SIN((%s - longitude) * pi()/180 / 2), 2) )) as
    distance FROM %s
    HAVING distance >= %s AND distance <= %s AND user_id != %s AND user_gender = %s AND user_sex = %s AND age >= %s AND age <= %s', $latitude, $longitude, $longitude, $people, $distance_range[0], $distance_range[1], $user_id, $sexual_preference, $sexual_orientation, $age_range[0], $age_range[1] )) or _error(SQL_ERROR_THROWEN);

        if($get_users->num_rows > 0) {
            while($user = $get_users->fetch_assoc()) {
                $user['user_picture'] = $this->get_picture($user['user_picture'], $user['user_gender']);
                /* get the connection between the viewer & the target */
                $user['connection'] = $this->connection($user['user_id']);
                $user['sort'] = $user['user_fullname'];
                $user['type'] = 'user';
                $results[] = $user;
            }
        }
}

我尝试的是让用户首先根据用户名（$ people）查找用户，然后根据距离，性别，年龄，方向等对这些用户进行过滤。（$ get_users ）。目前它不断给出循环（它继续加载但没有出现结果）。如果仅通过注释$ get_users并将$ people更改为$ get_users来使用$ people SQL查询，则会加载结果。我已经检查过数据库中的拼写错误（MyISAM）。我的代码中有错误或错过了什么吗？

我要感谢所有事先以任何方式提供帮助的人。

Answer 1

要解决我自己的问题，以便将来可以帮助某人...首先，我没有将变量放在secure（）函数中。其次，我调整了SQL查询，所以我只需要1.在下面你会找到正确的工作代码。

    public function search_quick($query) {
    global $db, $system;
    $results = array();

    $person = $db->query(sprintf("SELECT * FROM users WHERE user_id = %s AND user_token = %s", secure($_COOKIE[$this->_cookie_user_id], 'int'), secure($_COOKIE[$this->_cookie_user_token]) )) or _error(SQL_ERROR_THROWEN);
        if($person->num_rows > 0) {
            $this->_data = $person->fetch_assoc();
        }

    $user_id = $this->_data['user_id'];
    $latitude = $this->_data['latitude'];
    $longitude = $this->_data['longitude']; 
    $user_gender = $this->_data['user_gender'];
    $user_sex = $this->_data['user_sex'];
    $sexual_preference = $this->_data['sexual_preference'];
    $sexual_orientation = $this->_data['sexual_orientation'];
    $age_range = explode(',',$this->_data['age_range']);
    $distance_range = explode(',',$this->_data['distance_range']);

    $get_users = $db->query(sprintf('SELECT *,
3956 * 2 * ASIN(SQRT( POWER(SIN((%s - latitude) * pi()/180 / 2), 2) + COS(%s * pi()/180) * COS(latitude * pi()/180) *
POWER(SIN((%s - longitude) * pi()/180 / 2), 2) )) as
distance FROM users
HAVING distance >= %s AND distance <= %s AND user_fullname LIKE %s AND user_id != %s AND user_gender = %s AND user_sex = %s AND age >= %s AND age <= %s LIMIT %s', secure($latitude), secure($longitude), secure($longitude), secure($distance_range[0]), secure($distance_range[1]), secure($query, 'search'), secure($user_id), secure($sexual_preference), secure($sexual_orientation), secure($age_range[0]), secure($age_range[1]), secure($system['min_results'], 'int', false) )) or _error(SQL_ERROR_THROWEN);

    if($get_users->num_rows > 0) {
        while($user = $get_users->fetch_assoc()) {
            $user['user_picture'] = $this->get_picture($user['user_picture'], $user['user_gender']);
            /* get the connection between the viewer & the target */
            $user['connection'] = $this->connection($user['user_id']);
            $user['sort'] = $user['user_fullname'];
            $user['type'] = 'user';
            $results[] = $user;
        }
    }

}

SQL根据经度纬度选择用户和过滤器距离

1 个答案: