我有两个数据库集合Agency & Program
,其中Agency
可以有许多programs
,所有进一步的概念实现仅使用程序。所以我创建了两个POJO
public class Agency implements Serializable {
@DocumentField(DocumentField.Type.ID)
private String agencyId;
@DocumentField(DocumentField.Type.KEY)
@SerializedName("AGENCYNAME")
private String agencyName;
@SerializedName("SHORTNAME")
private String shortName;
@Expose(serialize = false, deserialize = true)
@SerializedName("PROGRAMS")
private List<Program> programs;
// Other fields with Getter & Setters
}
public class Program implements Serializable {
@DocumentField(DocumentField.Type.ID)
private String programId;
@SerializedName("PROGRAMNAME")
private String programName;
@DocumentField(DocumentField.Type.KEY)
@SerializedName("SHORTNAME")
private String shortName;
@SerializedName("AGENCY")
private Agency agency;
// Other fields with Getter & Setters
}
当我运行AQL : for a in AGENCY return merge(a, {PROGRAMS: (for p in PROGRAMS FILTER p.AGENCY == a._id return p)})
我得到了以下JSON
[
{
"AGENCYNAME": "Dummy Agency 1",
"SHORTNAME": "DA1",
"_id": "AGENCY/1062620",
"_key": "1062620",
"_rev": "_URnzj-C---",
"PROGRAMS": [
{
"_key": "DA1DP1",
"_id": "PROGRAMS/DA1DP1",
"_rev": "_UQ6dGOG---",
"AGENCY": "AGENCY/1062620",
"PROGRAMNAME": "DA1 Dummy Program 1",
"SHORTNAME": "DA1DP1"
}
]
},
{
"AGENCYNAME": "Dummy Agency 2",
"SHORTNAME": "DA2",
"_id": "AGENCY/1062358",
"_key": "1062358",
"_rev": "_URnzj-C---",
"PROGRAMS": [
{
"_key": "DA2DP1",
"_id": "PROGRAMS/DA2DP1",
"_rev": "_UQ6dGOG---",
"AGENCY": "AGENCY/1062358",
"PROGRAMNAME": "DA2 Dummy Program 1",
"SHORTNAME": "DA2DP1"
}
]
}
]
当我从arangodb-java-driver 4.1
运行此查询时,它会在反序列化时抛出异常
com.arangodb.velocypack.exception.VPackValueTypeException: Expecting type OBJECT
如果我评论来自Agency.java的这些行,它可以正常工作,但我需要在代理中使用List。
@Expose(serialize = false, deserialize = true)
@SerializedName("PROGRAMS")
private List<Program> programs;
在这种情况下有办法处理列表吗? 请建议一种方法来克服这个.. 谢谢:))
答案 0 :(得分:1)
在您的POJO Program
中,您有一个来自Agency
类型的字段代理商,但在您从数据库获取的JSON中,此字段来自类型字符串。将类型Agency
更改为String
,您的代码就可以使用。
<强>更新强>
要从您的查询中获得适合当前java bean的结果,请运行:
for a in AGENCY return merge(a, {PROGRAMS: (for p in PROGRAMS FILTER p.AGENCY == a._id return merge(p, {AGENCY: a}))})