Question

我的项目后端是arangodb。我有两个名为＆＃34; test＆＃34;和＆＃34;演示＆＃34;。我需要从这两个表中获取数据。我的数据是这样的：

测试

[
  {
    "firstName": "abc",
    "lastName": "pqr",
    "company": "abc Industries",
    "id": "1234"
  },
  {
    "firstName": "xyz",
    "lastName": "qwe",
    "company": "xyz Industries",
    "id": "5678"
  }
]

演示

[
  {
    "clientId": "1234",
    "subject": "test",
    "message": "testing",
    "priority": "High",
    "status": "closed",
    "id": "111111"
  },
  {
    "clientId": "1234", 
    "subject": "hiii",
    "message": "demo",
    "priority": "High",
    "status": "closed",
    "id": "222222"
  },
]

在这个测试的id中与demo的clientid相同。我需要从表中选择客户数据的数据＆＃34; 1234＆＃34;。我如何使用AQL（arango查询语言）实现这一点。我是arango的新手。任何建议都会非常明显。

Answer 1

您可以使用joins或subqueries执行此操作。

子查询的解决方案如下所示：

FOR t IN test
  FILTER t.id == @client
  RETURN { 
    test: t,
    demo: (FOR d IN demo
             FILTER d.clientId == @client
             RETURN d)
  }

@client是bind parameter，其中包含您的值1234。

结果是：

[
  {
    "test": {
      "_key": "140306",
      "_id": "test/140306",
      "_rev": "_Urbgapq---",
      "company": "abc Industries",
      "firstName": "abc",
      "id": "1234",
      "lastName": "pqr"
    },
    "demo": [
      {
        "_key": "140233",
        "_id": "demo/140233",
        "_rev": "_UrbfyAm---",
        "clientId": "1234",
        "id": "222222",
        "message": "demo",
        "priority": "High",
        "status": "closed",
        "subject": "hiii"
      },
      {
        "_key": "140200",
        "_id": "demo/140200",
        "_rev": "_UrbfjfG---",
        "clientId": "1234",
        "id": "111111",
        "message": "testing",
        "priority": "High",
        "status": "closed",
        "subject": "test"
      }
    ]
  }
]

Answer 2

For t in test
for d in demo 
filter t.id == d.clientId
filter t.id == @client
return {t,d}

Answer 3

FOR collection IN [test,demo]
FOR x IN collection
RETURN x

如何从arangodb中的两个集合中获取数据

3 个答案: