Question

示例：

seonds =“1015557”;

结果应该是：

11days 18h：05m：57s

如何在MySQL中执行此操作？

Answer 1

s/regular expression/replacement/flags

产生

select concat(
    format(floor(s / @day),0),
    'days ',
    time_format(sec_to_time(s % @day),'%Hh:%im:%ss') 
  ) formatted_date
from (select 1015557 s) t, (select @day = 3600 * 24);

Answer 2

您可以使用以下查询：

SELECT
  DATE_FORMAT(date('1970-12-31 23:59:59')
   + interval 1015557 second,'%j days %Hh:%im:%ss') as result;

<强>样品

mysql>     SELECT
    ->       DATE_FORMAT(date('1970-12-31 23:59:59')
    ->        + interval 1015557 second,'%j days %Hh:%im:%ss') as result;
+----------------------+
| result               |
+----------------------+
| 011 days 18h:05m:57s |
+----------------------+
1 row in set (0,00 sec)

mysql>

Answer 3

你可以尝试一下：

SET @seconds = 1015557;
SELECT CONCAT(
            FLOOR(TIME_FORMAT(SEC_TO_TIME(@seconds), '%H') / 24), 'days ',
            MOD(TIME_FORMAT(SEC_TO_TIME(@seconds), '%H'), 24), 'h:',
            TIME_FORMAT(SEC_TO_TIME(@seconds), '%im:%ss')
        )
AS Result

结果应该是：

11days 18h:05m:57s

希望这会有所帮助！

Answer 4

SELECT *
     , CONCAT( FLOOR(sec/3600),"hour ", FLOOR(MOD(sec,3600)/60),"min ",MOD(sec,60),"sec") 
        FROM table_1

MySQL：将秒数转换为天，分和小时

4 个答案: