Question

如何使用ActiveRecord执行此类操作？

Reservation.where("start..finish < 1 hour")

开始和完成是时间记录：

2.2.1 :009 > Reservation.last.start.class
  Reservation Load (1.1ms)  SELECT  "reservations".* FROM "reservations"  ORDER BY "reservations"."id" DESC LIMIT 1
  Reservation Load (1.1ms)  SELECT  "reservations".* FROM "reservations"  ORDER BY "reservations"."id" DESC LIMIT 1
 => ActiveSupport::TimeWithZone

感谢。

Answer 1

如果你正在使用Postgres，你可以使用其中一个time and date functions

Reservation.where("(finish - interval '1 hour') < start")

Answer 2

@reservationsWithinInterval1 = Reservation.where('startdate >= ? AND startdate < ? , @reservation.startdate, @reservation.enddate)

@reservationsWithinInterval2 = Reservation.where('enddate >= ? AND enddate < ?, @reservation.startdate, @reservation.enddate)

然后检查是否

if @reservationsWithinInterval1.count > 0 || @reservationsWithinInterval2.count>0
flash[:notice] = 'Select different time. Car already reserved in this time'

ActiveRecord查询比较时间间隔

2 个答案: