Question

所以我使用this帖子作为参考，但是我想根据15分钟的时间段计算所有行。

这是我到目前为止所做的：

SELECT      DateAdd(minute, DateDiff(minute, 0, [datetime]), 0) as Timestamp, 
            Count(*) as Tasks
FROM        [table]
GROUP BY    DateAdd(minute, DateDiff(minute, 0, [datetime]), 0)
ORDER BY    Timestamp

这非常适合每分钟获取行数，但我需要15分钟...... 所以我改变了：

DateAdd(minute, DateDiff(minute, 0, [datetime]), 0)

到

DateAdd(minute, DateDiff(minute, 0, [datetime]), 15)

然而，这只是提前15天推出日期。

感谢任何帮助！

Answer 1

要15分钟，除以15（然后再乘以）：

SELECT      DateAdd(minute, 15*(DateDiff(minute, 0, [datetime]) / 15), 0
                   ) as Timestamp, 
            Count(*) as Tasks
FROM        [table]
GROUP BY    (DateDiff(minute, 0, [datetime]) / 15)
ORDER BY    Timestamp;

SQL Server执行整数除法。如果您想明确表达自己的意图，请使用FLOOR()。

Answer 2

SELECT  ROUND(DATEDIFF(SECOND,{d '1970-01-01'},[datetime])/(15 * 60),0) as Timestamp, 
            Count(*) as Tasks
FROM   [table]
GROUP BY    ROUND(DATEDIFF(SECOND,{d '1970-01-01'},[datetime])/(15 * 60),0)
ORDER BY    Timestamp

Answer 3

如果整数除法对您造成问题，可以选择以下选项。它将日期时间转换为浮点数，然后使用floor（）。

SELECT      convert(varchar,cast(round(floor(cast([datetime] as float(53))*24*4)/(24*4),5) as smalldatetime),108)  as Timestamp, 
            Count(*) as Tasks
FROM        [table]
GROUP BY    convert(varchar,cast(round(floor(cast([datetime] as float(53))*24*4)/(24*4),5) as smalldatetime),108)
ORDER BY    Timestamp

我通常会将（24 * 4）更改为96（一天中15分钟的间隔数），但我想我会离开它，以便人们可以看到如何在其他时间段内调整它。

SQL查询按时间间隔

3 个答案: