Question

我有一个查询，它根据时间返回记录，如

+-------------+--------------+
| RenewalTime | RenewalCount |
+-------------+--------------+
|           1 |         2345 |
|           2 |          189 |
|           3 |          789 |
|           4 |         7676 |
|           5 |         9876 |
|           6 |         9762 |
+-------------+--------------+

但我希望将其显示如下，其中显示基于5分钟组的数据

+-------------+--------------+
| RenewalTime | RenewalCount |
+-------------+--------------+
| 0-5         |         2345 |
| 5-10        |          189 |
+-------------+--------------+

Select Round((Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 *     60,0) RenewalTime, count(1) RenewalCount
from refill,subscription_interval i where Trunc(Refill_Date) > '18-Nov-13'
And (Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 * 60 > 0
and (cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 < 1000
group by Round((Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 * 60,0)
order by RenewalTime;

Answer 1

你可以试试这个逻辑：

SELECT
      CASE
          WHEN YOURCOL1 <= 5
          THEN
              '1-5'
          WHEN YOURCOL1 <= 10
          THEN
              '6-10'
          ELSE
              'others'
      END
          AS YOURCOL1,
      COUNT ( YOURCOL2 ) AS N
FROM
      YOURTABLE
GROUP BY
      CASE
          WHEN YOURCOL1 <= 5
          THEN
              '1-5'
          WHEN YOURCOL1 <= 10
          THEN
              '6-10'
          ELSE
              'others'
      END;

Answer 2

我认为这个查询可以创建你想要的东西：

select to_char((t1.RenewalTime-1)*5)|| '-' ||to_char(t1.RenewalTime*5) as RenewalTime,RenewalCount 
 from
  (Select Round((Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 *     60,0) RenewalTime, count(1) RenewalCount
  from refill,subscription_interval i where Trunc(Refill_Date) > '18-Nov-13'
  And (Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 * 60 > 0
  and (cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 < 1000
  group by Round((Cast(i.Modification_Date As Date) - Cast(Refill_Date As Date)) * 24 * 60,0)
  order by RenewalTime)t1
where t1.RenewalTime < 3;

Answer 3

我会将此RenewTime转换为5分钟间隔，如下所示：

((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 /5

接下来，我会使用floor函数来区分一个5分钟的组：

floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)

接下来，我会将其转换为RenewalTime列所需的文本，如下所示：

to_char( 5 * floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)) ||' - ' || to_char( 5 * (floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)+1))

间隔是这样的：

0＆lt; = renewal_time＆lt; 5 ==＆gt; '0 - 5'

5＆lt; = renewal_time＆lt; 10 ==＆gt; '5 - 10'

10＆lt; = renewal_time＆lt; 15 ==＆gt; '10 - 15'

15＆lt; = renewal_time＆lt; 20 ==＆gt; '15 - 20'

这导致了这个sql语句。

select
to_char( 5 * floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)) || ' - ' || to_char( 5 * (floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5) +1)) RenewalTime
   count(1) renewal_count
from refill,
   subscription_interval i
where trunc(refill_date) > to_date('18-nov-13', 'dd-mon-yy')
   and (cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 > 0
   and (cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60 < 1000
group by
to_char( 5 * floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5)) || ' - ' || to_char( 5 * floor((cast(i.modification_date as date) - cast(refill_date as date)) * 24 * 60/ 5) +1)
order by 1;

按时间间隔对组进行SQL查询

3 个答案: