Question

我必须合并两个SQL查询才能在一个地方获取值。我想显示年初至今和周日显示一张表中具有相同猫的数量和单位

SQL查询

select 
    `EmpsID`, `CAT`, `CHK_DATE`, 
    SUM(AMOUNT) as CurrentAmount,
    SUM(UNITS) as CurrentUnits 
from 
    `pays` 
where 
    `EmpsID` = 'SEMLAD01' and 
    `CAT` in ('Salary Pay', 'TRUCK ALLOWANCE', 'Expense Reimbursement', 'BONUS  (Accrued)', 'Phone Reimbursement') and 
    date(`CHK_DATE`) = '2016-11-12' 
group by 
    `CAT`

第二次查询：

select 
    `EmpsID`, `CAT`, `CHK_DATE`, 
    SUM(AMOUNT) as ytdAmount,
    SUM(UNITS) as ytdUnits 
from 
    `pays` 
where 
    `EmpsID` = 'SEMLAD01' and 
    `CAT` in ('Salary Pay', 'TRUCK ALLOWANCE', 'Expense Reimbursement', 'BONUS  (Accrued)', 'Phone Reimbursement') and 
    date(`CHK_DATE`) <= '2016-11-12' 
group by 
    `CAT`

表格结构

 EmpsID       CAT               YTDAmount   YTDUnits   currentAmount     currentunit
SEMLAD01   BONUS                 3000.00      0.00        0.00      0.00
SEMLAD01   Expense               1307.90      0.00       50.00     
SEMLAD01   Phone Reimbursement    272.00     50.00     1840.00      0.00
SEMLAD01   Salary Pay           60153.74   1840.00        0.00      0.00
SEMLAD01   TRUCK ALLOWANCE       4246.26      0.00

Answer 1

     select `EmpsID`, `CAT`, `CHK_DATE`, SUM(AMOUNT) as CurrentAmount,SUM(UNITS) as CurrentUnits 
     ,sum(case when date(`CHK_DATE`) = '2016-11-12'  then AMOUNT else 0 end) as '2016-11-12Amount' ,
      ,sum(case when date(`CHK_DATE`) = '2016-11-12'  then UNITS else 0 end) as '2016-11-12Units' ,
    from `pays` where `EmpsID` = 'SEMLAD01' and 
    `CAT` in ('Salary Pay', 'TRUCK ALLOWANCE', 'Expense Reimbursement', 
    'BONUS  (Accrued)', 'Phone Reimbursement')and date(`CHK_DATE`) <= '2016-11-12' 
     group by `CAT`

合并两个查询以获取SQL中的组合值

1 个答案: