Question

请帮助合并这两个查询，我尝试使用UNION并获得结果错误

- 第一次查询

select  p.pegawainama,r.pegawainid, sum(cast(round(r.besarpotongan,0) as int)) as totalpotnondinas 
from 
    rpotongan r
inner join 
    pegawai p on p.pegawainid=r.pegawainid
where 
    r.nojenpot not in (1,7,6,12,14)
    --and r.pegawainid = '6290134A'
    and r.bulan = '3'
    and r.tahun = '2012'
    and p.kodebayar = '152012'
group by
    r.pegawainid,
    p.pegawainama
order by
    p.pegawainama,
    sum(cast(round(r.besarpotongan,0) as int))

- 第二次查询

select p.pegawainama, r.pegawainid, sum(cast(round(r.besarpotongan,0) as int)) as totalpotdinas from rpotongan r 
inner join 
    pegawai p on p.pegawainid=r.pegawainid
where 
    r.nojenpot in (1,7,6,12,14)
    --and r.pegawainid = '6290134A'
    and r.bulan = '3'
    and r.tahun = '2012'
    and p.kodebayar = '152012'
group by
    r.pegawainid,
    p.pegawainama
order by
    p.pegawainama,
    sum(cast(round(r.besarpotongan,0) as int))

Answer 1

要使用UNION，您需要使用相同的列名，因此一个查询中不能totalpotnondinas而另一个查询中不能totalpotdinas。

您可以做的是调用两列totals并添加一个额外的列，指示哪个查询是数据源。例如：

select p.pegawainama,r.pegawainid, sum(cast(round(r.besarpotongan,0) as int)) as total,
'potnondinas' as src from rpotongan r inner join pegawai p on p.pegawainid=r.pegawainid 
where r.nojenpot not in (1,7,6,12,14) --and r.pegawainid = '6290134A' and r.bulan = '3'
and r.tahun = '2012' and p.kodebayar = '152012' group by r.pegawainid, p.pegawainama
order by p.pegawainama, sum(cast(round(r.besarpotongan,0) as int))

- 第二次查询

select p.pegawainama, r.pegawainid, sum(cast(round(r.besarpotongan,0) as int)) as total, 
'potdinas' as src from rpotongan r inner join pegawai p on p.pegawainid=r.pegawainid
where r.nojenpot in (1,7,6,12,14) --and r.pegawainid = '6290134A' and r.bulan = '3'
and r.tahun = '2012' and p.kodebayar = '152012' group by r.pegawainid, p.pegawainama
order by p.pegawainama, sum(cast(round(r.besarpotongan,0) as int))

如果省略合成src列，UNION将合并相同的结果。

Answer 2

不确定这两个不同的查询除了不同的别名之外是怎样的，但是ORDER BY中只能有一个UNION（错误消息应该已经告诉了你）。尝试：

select  p.pegawainama,r.pegawainid, sum(cast(round(r.besarpotongan,0) as int))
     as totalpotnondinas 
from 
    rpotongan r
inner join 
    pegawai p on p.pegawainid=r.pegawainid
where 
    r.nojenpot not in (1,7,6,12,14)
    --and r.pegawainid = '6290134A'
    and r.bulan = '3'
    and r.tahun = '2012'
    and p.kodebayar = '152012'
group by
    r.pegawainid,
    p.pegawainama
union all
select p.pegawainama, r.pegawainid, sum(cast(round(r.besarpotongan,0) as int))
    as totalpotnondinas 
from 
    rpotongan r 
inner join 
    pegawai p on p.pegawainid=r.pegawainid
where 
    r.nojenpot in (1,7,6,12,14)
    --and r.pegawainid = '6290134A'
    and r.bulan = '3'
    and r.tahun = '2012'
    and p.kodebayar = '152012'
group by
    r.pegawainid,
    p.pegawainama
order by
    pegawainama,
    totalpotnondinas;

如果您希望SUM()列在两个结果之间可以辨认，请在第一个查询中使用SUM... AS col1, NULL AS col2，在第二个查询中使用NULL AS col1, SUM... AS col2。

合并两个查询

2 个答案: