Question

我使用SFML和Box2d创建了一个简单的游戏。但我遇到了问题。物理时间取决于玩家的帧率。

我已经获得了该播放器的FPS，但我不确定如何获得相同的时间。我也没有发现任何公式......有人可以帮助我吗？

while (window.isOpen()) {

    sf::Event event;
    while (window.pollEvent(event)) {
        if (event.type == sf::Event::Closed)
            window.close();
    }

    window.clear();


    window.display();

    sf::Time time = clock.getElapsedTime();
    float fps = 1.0f / time.asSeconds();
    std::cout << 1.0f / time.asSeconds() << std::endl;
    world.getBWorld()->Step(60/1, 8, 3);
    clock.restart();
}

Answer 1

You need to use a delta time.

In graphics programming, the term delta time is usually used for variably updating scenery based on the elapsed time since the game last updated. Wikipedia

sf::Clock deltaClock;
while (window.isOpen()) {
{
    // ...
    sf::Time dt = deltaClock.Restart(); // Restart returns the elapsed time
}

Then you can move your player with:

mySprite.Move(velocity * dt.AsSeconds());

box2d - 计算每个FPS金额的相同时间

1 个答案: