Question

我有这种形式的SQL结果：

Id Amount1 Amount2 Amount3
1  10      10       12
2  20      13       14
3  30      15       15

我正在尝试将Id存储在Key中，将所有其他值存储在值

中

类似的东西：

{1=>{:Amount1=>"10", :Amount2=>"10", :Amount3=>"12"}, 2=>{:Amount1=>"20", :Amount2=>"13", :Amount3=>"14"}}

这是我目前所拥有的：

hashn = Hash.new

  sqlresult.each { |x|  
    hashn[x['PPS_Id']] = x['Gift_Card_Amount1']
    hashn[x['PPS_Id']] = x['Gift_Card_Amount2']
    hashn[x['PPS_Id']] = x['Gift_Card_Amount3']
}

我相信这会覆盖以前的价值，请你帮忙。

Answer 1

您也可以将数组分配给哈希键

像下面的东西

hashn= {}

  sqlresult.each { |x|  
    hashn[x['PPS_Id']] = [] unless hashn[x['PPS_Id']]
    hashn[x['PPS_Id']] << x['Gift_Card_Amount1']
    hashn[x['PPS_Id']] <<  x['Gift_Card_Amount2']
    hashn[x['PPS_Id']] << x['Gift_Card_Amount3']
  }

Answer 2

假设您的Sql Result是一个活动记录集合，这应该有效：

required_hash = {}
sqlresult.each do |obj|
  required_hash[obj.id] =
   { amount1: obj.amount1, amount2: obj.amount2, amount3: obj.amount3 }
end
required_hash

将多个sql结果值分配给同一个键

2 个答案: