Question

我尝试用Java制作Libgdx游戏，我必须画树。当我尝试制作和绘制树木是可以的，但它需要很多时间。所以我尝试生成一个数组中的所有分支并在之后绘制它，但我有一个渲染问题。

当我尝试制作和绘制树木时：

当我尝试先生成然后绘制树时，我只是在屏幕上看不到任何内容。但我觉得渲染相同的东西..

代码运行良好：

public void drawBranch(OrthographicCamera b2dCam, int pointX, int pointY, double directionX, double directionY, float size,
        int lineWidth, int recursion_number) {
    // Finding the End Point of the Vector(line) to draw it
    int x2 = (int) (pointX + directionX * size), y2 = (int) (pointY + directionY * size);
    // Drawing the line from initial to final point

    int lineWidth2 = getCurrentLenght(recursion_number, lineWidth);
    Vector2 start = new Vector2(pointX, pointY);
    Vector2 end = new Vector2(x2, y2);

    // Draw the line
    HelperGraphicsClass.DrawDebugLineToPPM(start, end, lineWidth2, getCurrentColor(recursion_number), b2dCam.combined);

    // If the maximum recursions are reached we need to stop
    if (recursion_number >= CURRENT_RECURSIONS) {           
        return;
    }

    // Finding the size of next branch by shrinking the current branch
    float new_branch_size = size / SHRINK_FACTOR;
    double directionX2;
    double directionY2;
    // Incrementing the recursion_number by 1
    int n2 = recursion_number + 1;

    // Finding the Direction Vector of the next branch
    directionX2 = Math.sin(ANGLE) * directionY + Math.cos(ANGLE) * directionX;
    directionY2 = -(Math.sin(ANGLE) * directionX) + Math.cos(ANGLE) * directionY;
    // Drawing the branch
    drawBranch(b2dCam, x2, y2, directionX2, directionY2, new_branch_size, lineWidth2, n2);

    // // Finding the Direction Vector of the corresponding branch on
    // the other
    // // side i.e. with angle = -ANGLE
    directionX2 = Math.cos(-ANGLE) * directionX + Math.sin(-ANGLE) * directionY;
    directionY2 = -Math.sin(-ANGLE) * directionX + Math.cos(-ANGLE) * directionY;
    // Drawing the twin branch
    drawBranch(b2dCam, x2, y2, directionX2, directionY2, new_branch_size, lineWidth2, n2);

}

代码运行错误：

public void saveBranch(OrthographicCamera b2dCam, int pointX, int pointY, double directionX, double directionY, float size,
        int lineWidth, int recursion_number) {
    // Finding the End Point of the Vector(line) to draw it
    int x2 = (int) (pointX + directionX * size), y2 = (int) (pointY + directionY * size);
    // Drawing the line from initial to final point
    // g.drawLine(pointX, pointY, x2, y2);
    int lineWidth2 = getCurrentLenght(recursion_number, lineWidth);
    Vector2 start = new Vector2(pointX, pointY);
    Vector2 end = new Vector2(x2, y2);

    memoryTreeBranchs.get(0).add(new TreeBranch(start, end, lineWidth2, getCurrentColor(recursion_number)));

    // If the maximum recursions are reached we need to stop
    if (recursion_number >= CURRENT_RECURSIONS) {
        return;
    }

    // Finding the size of next branch by shrinking the current branch
    float new_branch_size = size / SHRINK_FACTOR;
    double directionX2;
    double directionY2;
    // Incrementing the recursion_number by 1
    int n2 = recursion_number + 1;

    // Finding the Direction Vector of the next branch
    directionX2 = Math.sin(ANGLE) * directionY + Math.cos(ANGLE) * directionX;
    directionY2 = -(Math.sin(ANGLE) * directionX) + Math.cos(ANGLE) * directionY;
    // Drawing the branch
    saveBranch(b2dCam, x2, y2, directionX2, directionY2, new_branch_size, lineWidth2, n2);

    // // Finding the Direction Vector of the corresponding branch on
    // the other
    // // side i.e. with angle = -ANGLE
    directionX2 = Math.cos(-ANGLE) * directionX + Math.sin(-ANGLE) * directionY;
    directionY2 = -Math.sin(-ANGLE) * directionX + Math.cos(-ANGLE) * directionY;
    // Drawing the twin branch
    saveBranch(b2dCam, x2, y2, directionX2, directionY2, new_branch_size, lineWidth2, n2);

}

我画得那样：

public void drawGeneratedBranchs(OrthographicCamera b2dCam) {
    for (int i = 0; i < memoryTreeBranchs.size(); i++) {
        for (TreeBranch tb : memoryTreeBranchs.get(i)) {
            HelperGraphicsClass.DrawDebugLineToPPM(tb.getStart(), tb.getEnd(), tb.getLineWidth(), getCurrentColor(i + 1),
                    b2dCam.combined);
        }
    }
}

我感觉很糟糕，我看不出差异，因为2周我无法解决这个问题......

感谢您的帮助!!

如何在libgdx中正确绘制线条

0 个答案: