Question

我有多个json文件，看起来像下面的示例：

#sample json    
{"urlCurrent":"https://www.website1.com/inside/377/388/408/8002.html?utm_source=source&utm_medium=Click&utm_campaign=123","id":"00001"}
{"urlCurrent":"https://127.0.0.1/inside/414/756/765/34984.html","id":"00002"}
{"urlCurrent":"https://msdn.anything.com/en-us","id":"00002"}
{"urlCurrent":"https://web.something.com/","id":"00002"}

我希望json成为：

#result json    
{"urlCurrent":"https://www.website1.com/","id":"00001"}
{"urlCurrent":"https://127.0.0.1/","id":"00002"}
{"urlCurrent":"https://msdn.anything.com/","id":"00002"}
{"urlCurrent":"https://web.something.com/","id":"00002"}

我认为

sed -i 's/{regular expression}/\ /g' sample.json

用空格后替换任何东西，可以实现结果。但是，我不知道如何使用正则表达式来匹配我需要的模式。我也不知道应该搜索哪个关键字才能实现这一目标。

有没有办法截断urlCurrent成为我需要的结果？提前谢谢！

12/23更新这有效：

sed -E -i -r 's!(http|ftp|https)://([0-9a-zA-Z\.]+)([0-9a-zA-Z\/\.?#=_&%~+-]+)!\2!g' sample.json

Answer 1

sed -i -r 's/(.*:\/\/?[^\/]+\/?)[^\"]*(.*)/\1\2/' sample.json

使用sed和regex用空格替换json值

1 个答案: