我怎样才能匹配子串＆＃34; 2153846-11＆＃34; （有时仅由数字组成，例如＆＃34; 2153846＆＃34;，有时喜欢＆＃34; 2153846-11＆＃34;或＆＃34; 2153846_11＆＃34;，有时喜欢＆＃34; 2153846-1＆＃34 ;总是数字和第一组中的数字不小于5）以下内容：
"01/16/2015","2153846-11","2015-01-16 02:50:18.0","lch_demo_hidemi-19459072-2","","01/16/2015"
并将匹配的字符串替换为第一组（在破折号/下划线之前），删除第二组。
最终结果将是：
"01/16/2015","2153846","2015-01-16 02:50:18.0","lch_demo_hidemi-19459072-2","","01/16/2015"
该指令将写成一个独特的sed行，如
sed -e 's/...//g' < myfile
由于
答案 0 :(得分：0)
您可以使用此sed：
sed 's/"\([0-9]*\)[_-][0-9]*"/"\1"/g' file
"01/16/2015","2153846","2015-01-16 02:50:18.0","lch_demo_hidemi-19459072-2","","01/16/2015"
答案 1 :(得分：0)
您可以尝试以下sed命令。
$ echo '"01/16/2015","2153846-11","2015-01-16 02:50:18.0","lch_demo_hidemi-19459072-2","","01/16/2015"' | sed -r 's/"(2153846)([_-]11)?"/"\1"/g'
"01/16/2015","2153846","2015-01-16 02:50:18.0","lch_demo_hidemi-19459072-2","","01/16/2015"