ID增量不会在嵌套while循环中递增

Question

变量$ Item成功递增，而另一个变量$ Item2保持为“2”，我不知道为什么它以2开头。

下面是它的截图。

这是代码

$itemQuery = $this->DBase('Query', array( 0 => "SELECT * FROM `items`" ));
while ($GETITEM = $itemQuery->fetch_object()) {
       $itemrewardQuery = $this->DBase('Query', array( 0 => "SELECT * FROM `quests_rewards` WHERE QuestID = $id" ));
       while ($QUESTITEM = $itemrewardQuery->fetch_object()) {
              $Item = $GETITEM->id;
              $Item2 = $QUESTITEM->ItemID;                  
              if($Item == $Item2){
                 $temp .= '<td>'. $GETITEM->Name .'<span class="label label-success pull-right">TAKEN</span></td>';
              } else {
                 $temp .= '<td>'. $GETITEM->Name .'</td>';
              };
       }
       echo "{$temp}";
}

Answer 1

$itemQuery = $this->DBase('Query', array( 0 => "SELECT * FROM `items`" ));
while ($GETITEM = $itemQuery->fetch_object()) {
       $itemrewardQuery = $this->DBase('Query', array( 0 => "SELECT * FROM `quests_rewards` WHERE QuestID = $id" ));
       while ($QUESTITEM = $itemrewardQuery->fetch_object()) {
              $Item = $GETITEM->id;
              $Item2 = "";
              $Item2 = $QUESTITEM->ItemID;                  
              if($Item == $Item2){
                 $temp .= '<td>'. $GETITEM->Name .'<span class="label label-success pull-right">TAKEN</span></td>';
              } else {
                 $temp .= '<td>'. $GETITEM->Name .'</td>';
              };
       }
       echo "{$temp}";
}

在分配新值之前使$ item2 =“”。 我认为这应该有效。请试试。