Question

我想逐步将div id添加到输出的图像中，但无法弄清楚如何使其正常工作。例如，第一个图像输出将具有＆＃34; .featured_1＆＃34;，下一个将具有＆＃34; .featured_2＆＃34;等

代码我正在使用

if( function_exists('dfi_get_featured_images') ){
   $featuredImages = dfi_get_featured_images();

   //Now loop through the image to display your image

   if( !is_null($featuredImages) ){

        $links = array();

        foreach($featuredImages as $images){
            $thumb = $images['thumb'];
            $fullImage = $images['full'];

            $links[] = "<li class='zoom'><img class='zoomImg' src='{$thumb}' alt='' height='{$height}' width='{$width}' /></li>";
        }

        foreach($links as $link){
          echo $link;
        }
        echo "<div style='clear:both'></div>";
        echo "</ul>";
     }

}

我尝试失败

    $i=1
    foreach($featuredImages as $images){
        $thumb = $images['thumb'];
        $fullImage = $images['full'];

        $links[] = "<li class='zoom featured_".$i."'><img class='zoomImg' src='{$thumb}' alt='' height='{$height}' width='{$width}' /></li>";
        $i++;
    }

Answer 1

“我使用的代码会产生意外的T_FOREACH错误”

$i=1
foreach($featuredImages as $images){

您有语法错误（缺少分号）

$i=1;
foreach($featuredImages as $images){

除此之外，还有很多代码可以满足您的需求

    foreach($featuredImages as $i=>$images){
        echo "<li class='zoom'><img class='zoomImg' src='".$images['thumb']."' alt='' height='{$height}' width='{$width}' /></li>";
    }

循环中增加div id

1 个答案: