Question

我有一个由此查询填充的下拉列表：

$sql = "SELECT DISTINCT CAST(MR_ID AS INT) AS MR_ID FROM Stage_Rebate_Index";

然后我有一个表，它会根据下拉列表的选择在表中显示值。我用这个查询来做到这一点。一切正常！

$sql_one = "SELECT CAST(Supp_ID AS INT) AS Supp_ID, CAST(MR_ID AS INT) AS MR_ID FROM Stage_Rebate_Index WHERE MR_ID = '$mr_id'";

但是，我必须进行一些更改，这是我需要填充下拉列表的查询。

$sql = "
SELECT DISTINCT
       CONCAT(CAST(t1.MR_ID AS INT),' - ', COALESCE(t2.MR_Name, '')) AS MR_ID,
       t1.MR_ID AS sort_column 
FROM Stage_Rebate_Index t1
      LEFT JOIN Stage_Rebate_Master t2
         ON t2.MR_ID = t1.MR_ID
ORDER BY sort_column";

这是我用来根据下拉列表的选择在表格中显示值的查询。但是，现在它无论如何都无法运作。无论何时进行选择，唯一显示的是表头。为什么是这样！？这让我发疯，我无法解决这个问题。

$sql_one = "
SELECT 
       CONCAT(CAST(t1.MR_ID AS INT),' - ', COALESCE(t2.MR_Name, '')) AS MR_ID,
       t1.MR_ID AS sort_column, 
       CAST(Supp_ID as INT) AS Supp_ID
FROM Stage_Rebate_Index t1
      LEFT JOIN Stage_Rebate_Master t2
         ON t2.MR_ID = t1.MR_ID
WHERE  
  CONCAT(CAST(t1.MR_ID AS INT),' - ', t2.MR_Name) = LTRIM(RTRIM('$mr_id'))
ORDER BY sort_column";

编辑：我从ajax函数调用的test-table.php脚本......

<?php
$host="xxxxxxxx"; 
$dbName="xxxxx"; 
$dbUser="xxxxxxxxxxx"; 
$dbPass="xxxxxxxxx";

$mr_id = $_POST['mr_name'];

$dbh = new PDO( "sqlsrv:server=".$host."; Database=".$dbName, $dbUser, $dbPass);
$dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
//$sql = "SELECT DISTINCT CAST(MR_ID AS INT) AS MR_ID FROM Stage_Rebate_Index WHERE MR_ID = '$mr_id'";
//$sql_one = "SELECT CAST(Supp_ID AS INT) AS Supp_ID, CAST(MR_ID AS INT) AS MR_ID FROM Stage_Rebate_Index WHERE MR_ID = '$mr_id'";

/*$sql_one = "
SELECT 
       CONCAT(CAST(t1.MR_ID AS INT),' - ', COALESCE(t2.MR_Name, '')) AS MR_ID,
       t1.MR_ID AS sort_column, 
       CAST(Supp_ID as INT) AS Supp_ID
FROM Stage_Rebate_Index t1
      LEFT JOIN Stage_Rebate_Master t2
         ON t2.MR_ID = t1.MR_ID
WHERE  
  CONCAT(CAST(t1.MR_ID AS INT),' - ', t2.MR_Name) = LTRIM(RTRIM('$mr_id'))
ORDER BY sort_column";*/

$sql_one = "
SELECT ID_Name, CAST(Supp_ID as INT) as Supp_ID
FROM Stage_Rebate_Index
WHERE ID_Name = LTRIM(RTRIM('$mr_id'));";

//echo $sql_one;

//$users = $dbh->query($sql);
$users_one = $dbh->query($sql_one);
?>

<html>
    <body>

        <!-- Table -->
<p> 
    <div id="table_div">
        <table border="1" id="index_table" class="ui-widget ui-widget-content">
            <thead>
                <tr class="ui-widget-header">
                <td>MR ID</td>
                <td>Supplier ID</td>
                </tr>
            </thead>
            <?php foreach($users_one->fetchAll() as $supp) { ?>
            <tr>
                <td class="mr_id"><?php echo $supp['ID_Name'];?></td>
                <td class="supp_id"><?php echo $supp['Supp_ID'];?></td>
            </tr>
            <?php } ?>
        </table>
    </div>

    </body>
    </html>

我的查询在数据库中工作但不在我的脚本中

0 个答案: