Question

我在pge上有一个按钮，它从php页面获取json数据，

数据似乎到了好但我已经经历了数百个例子，我似乎无法引用返回的数据，这是我的脚本：

以前评论中的编辑脚本

 $('#geo_batch').click(function (){
            var ajax_load = "<label><img src='/images/icons/loadinfo.gif' alt='saving location...' /> Loading data...</label>";
            $("#batch_detail").html(ajax_load);
            $('#batch_buttons').hide();
            var form = $("form"); //Grab the form element from the DOM 
            //alert(form.serialize());
            var mydata = form.serialize();
            $.ajax({  
                type: "POST",  
                url: 'geo_getupdate_list.php', 
                data: mydata,  
                datatype: 'json',
                success: function(dat) {
                    alert('dat:'+ typeof dat ) //RETURNS STRING
                    //alert(dat.location[0].id_mdt); //RETURNS UNDEFINED
                    // Cache the batch_detail element
                    var $detail = $("#batch_detail").html('<label>Locations have been retrieved:<br>' + dat + '<label>');
                    $('#batch_buttons').show();
                    // Instead of several .append() calls on the same element, create a 
                    //   single string, and do one.
                    var appendString = '';
                    for(var key in dat) { alert(key); return false; };
                    /*for(i=0; i < count; i++){
                        appendString += 'display address: ' + data.location[i].displayaddr_mdt + 'flag: ' + data.location[i].flag_mdt;
                    }*/
                    $detail.append(appendString);
                }, 
                error: function(dat) { //Triggered if an error communicating with server   
                     //alert('fail');
                     $("#batch_detail").html('<label>There was an error: '+dat+'<label>');  
                     $('#batch_buttons').show();
                }
            });  
            return false; //Ignore the default behavior of the button click  
        });

返回的json是：

{"location":[{"id_mdt":"5","idetp_mdt":"1","name_mdt":null,"geoaddr_mdt":null,"displayaddr_mdt":"31a Arundel Gardens London W11 2LW","telephone_mdt":null,"email_mdt":null,"website_mdt":"http:\/\/","lat_mdt":"51.513561","lng_mdt":"-0.206519","active_mdt":"1","flag_mdt":"1","id_etp":"1","name_etp":"Stockist","icon_etp":null},{"id_mdt":"1","idetp_mdt":"1","name_mdt":null,"geoaddr_mdt":null,"displayaddr_mdt":"via todde 29 Ales Sardegna 09091","telephone_mdt":null,"email_mdt":null,"website_mdt":"http:\/\/","lat_mdt":"39.7670964","lng_mdt":"8.813689","active_mdt":"1","flag_mdt":"1","id_etp":"1","name_etp":"Stockist","icon_etp":null},{"id_mdt":"4","idetp_mdt":"1","name_mdt":null,"geoaddr_mdt":null,"displayaddr_mdt":"31a Arundel Gardens London W11 2LW","telephone_mdt":null,"email_mdt":null,"website_mdt":"http:\/\/","lat_mdt":"51.513561","lng_mdt":"-0.206519","active_mdt":"1","flag_mdt":"1","id_etp":"1","name_etp":"Stockist","icon_etp":null},{"id_mdt":"3","idetp_mdt":"1","name_mdt":null,"geoaddr_mdt":null,"displayaddr_mdt":"31a Arundel Gardens London W11 2LW","telephone_mdt":null,"email_mdt":null,"website_mdt":"http:\/\/","lat_mdt":"51.513561","lng_mdt":"-0.206519","active_mdt":"1","flag_mdt":"1","id_etp":"1","name_etp":"Stockist","icon_etp":null},{"id_mdt":"6","idetp_mdt":"1","name_mdt":null,"geoaddr_mdt":null,"displayaddr_mdt":"31a Arundel Gardens London W11 2LW","telephone_mdt":null,"email_mdt":null,"website_mdt":null,"lat_mdt":"51.513561","lng_mdt":"-0.206519","active_mdt":"1","flag_mdt":"1","id_etp":"1","name_etp":"Stockist","icon_etp":null},{"id_mdt":"7","idetp_mdt":"1","name_mdt":"Test","geoaddr_mdt":null,"displayaddr_mdt":"31a Arundel Gardens London W11 2LW","telephone_mdt":null,"email_mdt":null,"website_mdt":null,"lat_mdt":"51.513561","lng_mdt":"-0.206519","active_mdt":"1","flag_mdt":"1","id_etp":"1","name_etp":"Stockist","icon_etp":null}]}

如何访问数组中的数据？

我在这里和其他地方尝试了很多例子，我无法工作。我认为它可能与它所拥有的返回的json对象有关[我认为它是错误的符号吗？

php我必须生成json如下：

//have defined a recordset called $rs_locations
$rows = array();
while($r = mysql_fetch_assoc($rs_locations)) {
    $rows[] = $r;
}
$jsondata = json_encode($rows);
// trying to strip out the [ ] brackets but doesn't work
str_replace ("[", "", $jsondata);
str_replace ("]", "", $jsondata);
echo($jsondata);

任何人的想法，我很困惑，谢谢

Answer 1

编辑：您的dataType属性拼写错误。

应该是dataType，而不是datatype。

另外，请尝试将data参数更改为其他名称，例如dat。在$.ajax()来电设置data属性之前，我已经看到了相关问题。

success: function( dat ) {
   // Then change all references from data to dat

尝试使用success:回拨。

您多次获取相同的#batch_detail元素并不断在该元素上调用.append()。

这样你就可以缓存对元素的引用，创建一个要追加的String，然后在循环结束后执行一次追加。

您遇到的具体问题是您需要直接引用data.location存储的数组。

 success: function(dat) {
     // Cache the batch_detail element
     var $detail = $("#batch_detail").html('<label>Locations have been retrieved:<br>' + dat + '<label>');
     $('#batch_buttons').show();
     var count = dat.location.length - 1;
       // Instead of several .append() calls on the same element, create a 
       //   single string, and do one.
     var appendString = '';
     for(i=0; i < count; i++){
         appendString += 'display address: ' + dat.location[i].displayaddr_mdt + 'flag: ' + dat.location[i].flag_mdt;
     }
     $detail.append( appendString );
 },

Answer 2

如果我的脚本正确，您必须先从location获取data数组：

var locations = data.location;
for(var location in locations) {
    console.debug(locations[location]);
}

jquery json循环数据 - 只是无法弄清楚这一点

2 个答案: