Question

这是一个已经工作了一段时间的作业问题，但我似乎无法弄清楚其余部分。

你的程序将计算一些咖啡袋的价格。   你会先询问用户;他们想要多少袋咖啡。
  每袋的价格是每个5.50美元。你的价格还必须包括   装运这批货物需要多少箱子。有   提供三种尺寸的运输箱。一个大盒子可容纳20个袋子，一个   中型箱可容纳10个袋子，一个小盒子最多可容纳5个袋子。您   不能运送不满的大中型箱子。（但小的   可以有1-5个袋子）每箱的运费价格很大=   1.80美元，中等= 1.00美元，小= 0.60美元。一个最终的价格变化是   可能的折扣。使用下面的图表来计算   咖啡价格的折扣（不包括运费）。
0-24 bags    - no discount        
25-49 bags   – 5% discount
50-99 bags   – 10% discount       
100-149 bags – 15% discount
150-199 bags - 20% discount
200-299 bags - 25% discount
300 and up   - 30% discount
不在盒子上使用折扣。使用if语句或a 切换语句来完成这项工作。

import java.util.Scanner;

public class discount {
   public static void main(String[] args) {

   Scanner key = new Scanner(System.in);
    System.out.println("Hello how are you? How many numberbags of coffee would you like?");

       double numberbag;
       double bag = 5.50;

       numberbag = key.nextDouble();
       System.out.println("Number of numberbags ordered: " + numberbag);
       double price = (numberbag * bag);    
       System.out.println("- $" + price);

   if (numberbag < 24 && numberbag > 0) {
      System.out.println("no discount: $" + price);
   }
   else if (numberbag < 49 && numberbag > 25) {
      System.out.println("5% discount: $" + price * .05);    
   }
   else if (numberbag < 99 && numberbag > 50) {
      System.out.println("10% discount: $" + price  * .10);    
   }
   else if (numberbag < 149 && numberbag > 100) {
      System.out.println("15% discount: $" + price * .15);    
   }
   else if (numberbag < 199 && numberbag > 150) {
      System.out.println("20% discount: $" + price * .20);    
   }
   else if (numberbag < 299 && numberbag > 200) {
      System.out.println("25% discount: $" + price * .25);    
   }
   else {
      System.out.println("30% discount: $" + price * .30);
   }
   double small = ;
   double medium = 10; 
   double large = 20;

   double sp = 0.60;
   double mp = 1.00;
   double lp = 1.80;

   double Rl = numberbag%large;
   double Rm = Rl%medium;
   double Rs = Rm%small;

Answer 1

将其更改为此

       if (numberbag < 24 && numberbag > 0) {
              System.out.println("no discount: $" + price);
           }
           else if (numberbag < 49 && numberbag > 25) {
              System.out.println("5% discount: $" + (price - (price * .05)));    
           }
           else if (numberbag < 99 && numberbag > 50) {
              System.out.println("10% discount: $" + (price - (price * .10)));    
           }
           else if (numberbag < 149 && numberbag > 100) {
              System.out.println("15% discount: $" + (price - (price * .15)));    
           }
           else if (numberbag < 199 && numberbag > 150) {
              System.out.println("20% discount: $" + (price - (price * .20)));    
           }
           else if (numberbag < 299 && numberbag > 200) {
              System.out.println("25% discount: $" + (price - (price * .25)));    
           }
           else {
              System.out.println("30% discount: $" + (price - (price * .30)));
           }

Answer 2

回答你关于盒子的第二个问题。创建一个像这样的方法

public static double calculateBoxes(int y) {
    int remainder = y%20;
    int bigBox = y/20;
    int remainder2 = remainder%10;
    int medBox = remainder/10;
    int remainder3 = remainder2%5;
    int smallBox = remainder2/5;

    if (remainder3 == 0){

    }
    else{
        smallBox++;
    }

    double boxPrice = (bigBox*1.80)+(medBox*1.00)+(smallBox*.60);

    return boxPrice;
}

然后像你这样从你的主人那里打电话

calculateBoxes（numberBag）

无法想出这个问题。 Java的

2 个答案: