我正在使用SQL Server 2014,我的数据库中有一个名为MyTable的表。提取物如下所示:
protected
我需要转换此表,以便我的SQL查询输出如下:
Hotel Market Desc Jan16 Feb16
ABC France SUP HB 158 33
ABC France SUP AI 35 6
ABC France DLX HB 27 10
如何使用T-SQL实现此输出?在阅读了有关网络问题的一些内容之后,我相信UNPIVOT语法可能会起作用,但我完全不知道如何在此上下文中使用它。
答案 0 :(得分:1)
select Hotel , Market,[desc],marks,Date
from #c s
unpivot
(
marks
for date in (jan16, feb16)
) u;
或 2)
SELECT HOTEL ,MARKET,A.[DESC] MARKET,[DATE] ,V.[DESC]
FROM #C A
CROSS APPLY (VALUES('JAN16', JAN16),
('FEB16', FEB16))
V (DATE, [DESC]);
output
Hotel Market desc marks Date
ABC France SUP HB 158 Jan16
ABC France SUP HB 33 Feb16
ABC France SUP AI 35 Jan16
ABC France SUP AI 6 Feb16
ABC France DLX HB 27 Jan16
ABC France DLX HB 10 Feb16
答案 1 :(得分:0)
一种简单的方法是使用UNION
:
SELECT Hotel, Market, Desc, 'Jan16' AS Date, Jan16 AS Values
FROM MyTable
UNION ALL
SELECT Hotel, Market, Desc, 'Feb16', Feb16
FROM MyTable
如果你期望比这更复杂的东西,例如超过两列,然后您可以尝试使用UNPIVOT
。
答案 2 :(得分:0)
select *
from mytable unpivot ("values" for "date" in (Jan16,Feb16)) u
+-------+--------+--------+--------+-------+
| Hotel | Market | Desc | values | date |
+-------+--------+--------+--------+-------+
| ABC | France | SUP HB | 158 | Jan16 |
+-------+--------+--------+--------+-------+
| ABC | France | SUP HB | 33 | Feb16 |
+-------+--------+--------+--------+-------+
| ABC | France | SUP AI | 35 | Jan16 |
+-------+--------+--------+--------+-------+
| ABC | France | SUP AI | 6 | Feb16 |
+-------+--------+--------+--------+-------+
| ABC | France | DLX HB | 27 | Jan16 |
+-------+--------+--------+--------+-------+
| ABC | France | DLX HB | 10 | Feb16 |
+-------+--------+--------+--------+-------+