我正在进行网络API呼叫。我通过调用helper类中的post方法从我的类调用。所以我想将我在辅助类（alamofire响应）中收到的响应返回给完成请求的类。
MyClass的
static func postMethodRequest(parameters:Parameters, methodName:String) -> [String:Any]
{
let headers:HTTPHeaders = generateHeaders(methodType: "POST", methodName: methodName)
var responseDictionary:[String: Any] = ["OperationStatus":"Success"]
Alamofire.request("http:acaapi.idyas.net" + methodName, method: .post, parameters: parameters, encoding: JSONEncoding.default, headers: headers).responseJSON{ response in
//This control comes to this block after a delay i.e., once the response is received.
responseDictionary = response.result.value as! [String: Any]
print(responseDictionary)
}
return responseDictionary // This line of code does not wait for the response to be received. Hence the control goes to MyClass before the response is received.
}
WebServiceHelper：
<?php
namespace Http\Controllers;
use App\Http\Requests;
use App\Http\Requests\PrepareNoticeRequest;
use App\Provider;
use Illuminate\Http\Request;
class NoticesController extends Controller {
public function create() {
$providers = Provider::lists('name' , 'id');
return view('notices.create' , compact('providers'));
}
}
我希望该方法仅在收到响应后才返回responseDictionary。这可以通过Dispatchqueue或任何其他方式实现吗？
编辑：邓肯：我试着在这里理解这个问题。我想将响应返回给另一个类。它不仅仅是在alamofire响应块中调用一个函数。我无法将'return responseDictionary'代码放在块中。但我需要的是，我想在收到回复后返回responseDictionary。