Question

我试图在成功的AJAX调用中进行AJAX调用。我查看了类似的线程，看看我是否正确地进行了操作，看起来就像我一样。

我错过了什么？我收到了意外的令牌错误＆＃39;在第二个开头＃.ajax（{＆＃39; line。

$.ajax({
            type: "POST",
            url: "actionPages/billing.php",
            data: {
                custID: custID,
                credFName: credFName,
                credLName: credLName,
                credNum: credNum,
                credExpireMonth: credExpireMonth,
                credCVVNum: credCVVNum,
                credAddress: credAddress,
                credStreet: credStreet,
                credCity: credCity,
                credProvinState: credProvinState,
                credCountry: credCountry,
                credPostalZip: credPostalZip,
                credExpireYear: credExpireYear,
                dealID: dealID
            },
            dataType: 'json',
            success: function(response) {

                var credID = response;

                .ajax({
                    type: "POST",
                    url: "actionPages/order.php",
                    data: {
                        credID: credID,
                        custID: custID,
                        dealID: dealID
                    },
                    dataType: 'json',
                    success: function(response) {

                    },
                    error: function (e) { console.log(e); }
                });
            },
            error: function (e) { console.log(e); }
        });

Answer 1

你在第二次ajax电话前缺少一个$。这应该可以解决问题。

Answer 2

write $.ajax in inner ajax code    
$.ajax({
        type: "POST",
        url: "actionPages/billing.php",
        data: {
            custID: custID,
            credFName: credFName,
            credLName: credLName,
            credNum: credNum,
            credExpireMonth: credExpireMonth,
            credCVVNum: credCVVNum,
            credAddress: credAddress,
            credStreet: credStreet,
            credCity: credCity,
            credProvinState: credProvinState,
            credCountry: credCountry,
            credPostalZip: credPostalZip,
            credExpireYear: credExpireYear,
            dealID: dealID
        },
        dataType: 'json',
        success: function(response) {

            var credID = response;

            $.ajax({
                type: "POST",
                url: "actionPages/order.php",
                data: {
                    credID: credID,
                    custID: custID,
                    dealID: dealID
                },
                dataType: 'json',
                success: function(response) {

                },
                error: function (e) { console.log(e); }
            });
        },
        error: function (e) { console.log(e); }
    });

AJAX中的AJAX导致意外的令牌错误

2 个答案: