我一直在接受这个错误,并且对于我的生活,我无法弄清楚究竟是什么导致了它。我要做的是从数据库中检索一些数据并将其显示在页面上,但我无法做到。
xmlhttp.onreadystatechange = function () {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
if (xmlhttp.responseText != null || xmlhttp.responseText != "That email does not exist in our database") {
var json = JSON.parse(xmlhttp.responseText);
var image = json[0]; // or json["Data"]
document.getElementById("dp").innerHTML = image;
} else {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
}
}
xmlhttp.open("GET", "getemail.php?q=" + str, true);
xmlhttp.send();
这是我在
进行检索的文件$q = $_GET['q'];
$data = [];
if (!$link) {
die('Could not connect: ' . mysqli_error($link));
}
$sql="SELECT officer_name FROM officer WHERE email = '$q'";
$result = mysqli_query($link,$sql);
$getName = mysqli_fetch_assoc($result);
$name = $getName['officer_name'];
if($name == null){
echo "That email does not exist in our database";
} else {
$sql2="SELECT picture, officer_name FROM officer WHERE email = '$q'";
$result2 = mysqli_query($link,$sql2);
$getItems = mysqli_fetch_array($result2);
$pic = $getItems['picture'];
$name = $getItems['officer_name'];
$data = ["image" => "<img style='height:150px; width:150px;' src='image/" . $pic . "'>", "email" => "$q"];
echo $data;
}
mysqli_close($link);
控制台指向行“var json = JSON.parse(xmlhttp.responseText);”至于错误的位置。如果解决方案看起来有点明显,我很抱歉,我刚开始涉足这个问题。感谢您提供的任何帮助。
答案 0 :(得分:2)
这是一个非常靠近你的ajax。我没有你的js所引用的所有其他内容,因此部分内容将失败:
<script type="text/javascript" src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script type="text/javascript" src="http://code.jquery.com/ui/1.9.2/jquery-ui.js"></script>
<script>
$(document).ready(function() {
$("#clicker").click(function() {
var str = 'test';
$.ajax({
url: "getemail.php",
type: 'get',
data: { q: str },
success: function(response) {
if(response != null)
$("#dp").html(response);
else
$("#txtHint").html("That email does not exist in our database");
}
});
});
});
</script>
<div id="clicker">CLICK</div>
<div id="dp">load into</div>
<div id="txtHint">txtHint text hing</div>