我正在上传表单中的图片,表单已提交到Firebase数据库,我还希望将图片网址发送到Firebase数据库。
var {image} = this.state;
var {url} = this.state;
var that = this;
var storageRef = firebase.storage().ref('students_images/' + image.name);
storageRef.put(image).then(function(snapshot) {
that.setState({
url: snapshot.downloadURL
});
});
var studRef = firebaseRef.child('students');
var newStudRef = studRef.push().update({
name: val['name'].value,
email: val['email'].value,
age: val['age'].value,
date: val['jdate'].value,
course: val['course'].value,
imgUrl: url
});

但问题是图像URL来自异步函数,它需要稍微回馈URL,但表单立即被提交,因此imgUrl
的值设置为undefined。 / p>
答案 0 :(得分:2)
在里面提交你的表格然后阻止。
var storageRef = firebase.storage().ref('students_images/' + image.name);
storageRef.put(image).then(function (snapshot) {
that.setState({url: snapshot.downloadURL});
var studRef = firebaseRef.child('students');
var newStudRef = studRef.push().update({
name: val['name'].value,
email: val['email'].value,
age: val['age'].value,
date: val['jdate'].value,
course: val['course'].value,
imgUrl: snapshot.downloadURL
});
});
答案 1 :(得分:1)
问题是此语句that.setState({url: snapshot.downloadURL});
在回调中执行,表单提交在回调之外。
虽然在快照响应之后您将setState
正确,但在我们等待来自异步代码的响应时,会在回调之外放置表单提交代码。事实上,表单提交发生在setState
之前。
解决方案是在异步函数的回调中执行表单提交代码。另请注意State Updates May Be Asynchronous。
所以我建议你这样做:
var { image, url } = this.state;
var storageRef = firebase.storage().ref('students_images/' + image.name);
var studRef = firebaseRef.child('students');
var that = this;
storageRef.put(image).then(function(snapshot) {
var newStudRef = studRef.push().update({
name: val['name'].value,
email: val['email'].value,
age: val['age'].value,
date: val['jdate'].value,
course: val['course'].value,
imgUrl: snapshot.downloadURL
});
that.setState({ url: snapshot.downloadURL });
// ... do more things with 'snapshot' or 'newStudRef'
});