Question

我有一个POSTGRESQL更新语句，我尝试使用显式连接重写并需要一些帮助，以便识别NESTED select语句别名来执行外部UPDATE语句。不确定为什么＆＃34; se＆＃34;无法识别嵌套选择的别名。我知道我必须遗漏一些基本的东西。

任何帮助/指示将不胜感激。感谢。

错误我得到了：

ERROR:  schema "se" does not exist

********** Error **********

ERROR: schema "se" does not exist
SQL state: 3F000

这是我的代码：

UPDATE students
SET custom_400011449 = CAST(cfso1.label as integer)+1,
       custom_400011770 = 761 --'2016-2017' 
FROM (
       SELECT se2.student_id, cfso1.id, cfso1.label
       FROM students s
       INNER JOIN student_enrollment se2
       ON s.student_id = se2.student_id
       INNER JOIN school_gradelevels sg
       ON se2.grade_id = sg.id
       INNER JOIN custom_field_log_entries sle
       ON se2.student_id = sle.source_id
       LEFT JOIN custom_field_select_options cfso1 
       ON s.custom_400011449 = cfso1.id
       LEFT JOIN custom_field_select_options cfso2
       ON s.custom_400011770 = cfso2.id
       LEFT JOIN custom_field_select_options cfso3
       ON sle.log_field4::INT = cfso3.id
       WHERE se2.syear =2016
       AND s.custom_400011449 IS NOT NULL
       AND s.custom_400011898 IS NULL 
       AND s.custom_400011899 IS NULL
       AND sle.field_id = 15 --400010549 
       AND sle.log_field2 IS NULL 
       AND cfso2.label = '2015-2016'
       AND cfso3.label IN ('LE', 'NL-F', 'NL-S') 
       AND sg.short_name BETWEEN '01' AND '12' 
       AND (
              SELECT COUNT(school_date) 
              FROM student_enrollment se
              INNER JOIN attendance_calendar ac 
              ON se.calendar_id = ac.calendar_id
              WHERE se.student_id = se2.student_id
              AND se.syear =2016 --{SYEAR}
              AND ac.syear =2016 --{SYEAR}
              AND ac.school_date >= se.start_date 
              AND ac.school_date <= NOW() 
              AND (se.end_date IS NULL OR ac.school_date <= se.end_date) 
              AND se.custom_9 IS NULL 
              AND se2.start_date >= '2016-08-22' 
              GROUP BY se.student_id 
              HAVING COUNT(ac.school_date) >= 59) 
       >= 59) AS se
LEFT JOIN custom_field_select_options cfso1
ON se.cfso1.id = cfso1.id
WHERE students.student_id = se.student_id

Answer 1

我发现我的问题是在ON条件“se.cfso1.id”中出现语法错误。一旦我解决了问题就解决了。

postgresql更新语句中的模式错误

1 个答案: