Question

现在代码执行会在computer_move函数*下执行以下“if语句”。我希望它等待玩家点击另一个按钮。现在，代码在玩家点击按钮放置“o”之前放置x。

import tkinter as tk

board = tk.Tk()

def player_move(widget):
    if widget["o"] not in ("o", "x"):
        widget["text"] = "o"
        widget["state"] = "disabled"
        computer_move()

def computer_move():
    if i["text"] == "Open Space":
        i["text"] = "x"
        i["state"] = "disabled"
    else:
        c["text"] = "x"
        c["state"] = "disabled"
    if a["text"] and c["text"] == "x" or "o": # *
        b["text"] = "x"
        b["state"] = "disabled"

board.geometry("400x500")
board.title("Board")

buttons = []

a = tk.Button(board, text="x", state = "disabled")
a["command"] = lambda x=a:player_move(x)
a.grid(row=0, column = 0)
buttons.append(a)

board.mainloop()

Answer 1

代码没有设置x，但您可以在线

进行设置

 a = tk.Button(board, text="x", state= "disabled")

删除text="x", state="disabled"

顺便说一句：

widget["o"]不正确 - 按钮没有名称为"o"的媒体资源。
它有属性"text" - widget["text"] - 可能有值"o"或"x"

if a["text"] and c["text"] == "x" or "o":相当不正确。特别是

c["text"] == "x" or "o"

必须是

c["text"] == "x" or c["text"] == "o"

或

c["text"] in ("x", "o")

我想你试着做

if a["text"] in ("x", "o") and c["text"] in ("x", "o"):

最好将按钮保留在列表中 - 您可以使用for循环检查computer_move

中的所有按钮

import tkinter as tk

# --- functions ---

def player_move(btn):
    # if button is empty 
    if btn["text"] not in ("o", "x"):
        # then set `o` and disable button 
        btn["text"] = "o"
        btn["state"] = "disabled"
        # and make comuter move
        computer_move()

def computer_move():
    # check all buttons 
    for btn in buttons:
        # if button is empty 
        if btn["text"] not in ("o", "x"):
            # then set `x` and disable button 
            btn["text"] = "x"
            btn["state"] = "disabled"
            # and skip checking other buttons
            break

# --- main ---

board = tk.Tk()

board.geometry("400x500")
board.title("Board")

buttons = []

for row in range(3):
    for col in range(3):
        btn = tk.Button(board, width=1)
        btn["command"] = lambda x=btn:player_move(x)
        btn.grid(row=row, column=col)
        buttons.append(btn)

board.mainloop()

如何让python等待轮到它（tkinter）

1 个答案: