Question

import MySQLdb

db = MySQLdb.connect("localhost","root","password","database")
cursor = db.cursor()
cursor.execute("SELECT id FROM some_table")
u_data = cursor.fetchall()

>>> print u_data
((1320088L,),)

我在互联网上找到的东西让我直到这里：

string = ((1320088L,),)
string = ','.join(map(str, string))
>>> print string
(1320088L,)

我期望输出看起来像：

 #Single element expected result
 1320088L  
 #comma separated list if more than 2 elements, below is an example
 1320088L,1320089L

Answer 1

首先使用itertools.chain_fromiterable()展平嵌套元组，然后map()展开字符串和join()。请注意，str()会删除L后缀，因为数据不再是long类型。

>>> from itertools import chain
>>> s = ((1320088L,),)
>>> ','.join(map(str,chain.from_iterable(s)))
'1320088'

>>> s = ((1320088L,1232121L),(1320088L,),)
>>> ','.join(map(str,chain.from_iterable(s)))
'1320088,1232121,1320088'

注意，string不是一个好的变量名，因为它与string模块相同。

Answer 2

我认为string是包含长值的tuple tuple。

>>> string = ((1320088L,),)
>>> ','.join(str(y) for x in string for y in x if len(x) > 0)
'1320088'
>>>

e.g。有多个值

>>> string = ((1320088L,1232121L),(1320088L,),)
>>> ','.join(str(y) for x in string for y in x if len(x) > 0)
'1320088,1232121,1320088'
>>>

Answer 3

string = ((1320088L,),)
print(','.join(map(str, list(sum(string, ())))))
string = ((1320088L, 1232121L), (1320088L,),)
print(','.join(map(str, list(sum(string, ())))))

输出：

1320088
1320088,1232121,1320088

Python：将元组转换为逗号分隔的String

3 个答案: