Question

我需要在B列中重复的值，直到A列发生变化。

这是输入

<!DOCTYPE html>
<html data-ng-app="myApp">

<head>
  <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js"></script>
</head>

<body data-ng-controller="testController">
  <ng-form name="phoneInnerForm">
    <div>

      <div class="form-group" data-ng-repeat="item in items" ng-class="phoneInnerForm.phones{{$index}}.$error.maxlength ? 'phone_number_error': ''">
        <input type="text" class="form-control" id="InputAddPhone" name="phones{{$index}}" ng-model="item.number" ng-maxlength="50">
        <select class="form-control" ng-model="item.type">
          <option value=""></option>
          <option value="mobile">Mobile</option>
          <option value="work">Work</option>
          <option value="home">Home</option>
          <option value="fax">Fax</option>
          <option value="other">Other</option>
        </select>

        <div class="evy_email_dltbtn">
          <button type="button" class="btn btn-default btn_delete" ng-click="deleteItem($index);" title="Delete">Delete</button>
          <button ng-show="$last" type="button" class="btn btn-default btn_delete" ng-click="addItem();" title="Delete">Add</button>
        </div>
        <span ng-show="phoneInnerForm.phones{{$index}}.$error.maxlength" class="evy_user-preference_error">Phone number should not exceed 50 characters</span>
      </div>

    </div>
  </ng-form>
  <script>
    angular
      .module('myApp', [])
      .controller('testController', ['$scope',
        function($scope) {

          $scope.items = [{
            number: "",
            type: ""
          }];

          $scope.addItem = function() {
            $scope.items.push({
              number: "",
              type: ""
            });
          }

          $scope.deleteItem = function(index) {
            $scope.items.splice(index, 1);
          }

        }
      ]);
  </script>
</body>

</html>

预期输出

    Column A  Column B
     18         1
     18         0
     18         0
     18         0
     24         2
     24         0
     18         3
     18         0
     18         0
     18         0

Answer 1

如果first需要按transform移位列Series创建的Col A重复每个组的第一个值，则print (df['Col A'].ne(df['Col A'].shift()).cumsum()) 0 1 1 1 2 1 3 1 4 2 5 2 6 3 7 3 8 3 9 3 Name: Col A, dtype: int32 df['Col B'] = df.groupby(df['Col A'].ne(df['Col A'].shift()).cumsum())['Col B'] .transform('first') print (df) Col A Col B 0 18 1 1 18 1 2 18 1 3 18 1 4 24 2 5 24 2 6 18 3 7 18 3 8 18 3 9 18 3可以使用cumsum：< / p>

ls

Answer 2

A =[18,18,18,18,24,24,18,18,18,18]
def func(A):
    B = []
    b = 1
    for i in range(len(A)):
        if i == 0:
            B.append(b)
            continue
        if A[i] != A[i-1]:
            b += 1
            B.append(b)          
        else:
            B.append(b)
    return B

出：

[1, 1, 1, 1, 2, 2, 3, 3, 3, 3]

重复B列中的值，直到A列发生更改

2 个答案: