Question

我需要编写一个程序来存储12个月的总降雨量，然后显示总量，平均值，最高降雨量和最低降雨量的月份输出。我的程序运行但是我不知道如何使输出成为月份的数量，而不是那个月的降雨量。例如，当我有，输入第6个月的降雨：15.6我的输出应该是6而不是15.6。谢谢你的帮助。

import java.util.Scanner;

public class Rainfall
{
   public static void main (String [] args)
   {
       double[] rain = new double[12]; // The rainfall data

       getValues(rain);
       showValues(rain);
       System.out.println("The total rainfall for this year is: " + totalRain(rain));
       System.out.println("The average rainfall for this year is: " + averageRain(rain));
       System.out.println("The month with the highest amount of rain is: " + mostRain(rain));
       System.out.println("The month with the lowest amount of rain is: " + leastRain(rain));
    }

   /**
      showValues method
      @param  rain Display the rainfall array
   */
    public  static void showValues(double[] rain)
    {

    }

   /**
      getValues method
      @return The rain array filled with user input
   */
    public  static void getValues(double[] array)
    {
          Scanner scan = new Scanner(System.in);

          for (int i = 0; i < array.length; i++)
          {
                System.out.println("Enter rain fall for month " + (i + 1) + ".");
                array[i] = scan.nextDouble();
          }
    }

   /**
      getTotal method
      @return The total of the elements in
      the rainfall array.
   */

   public static double totalRain(double[] rain)
   {
       double total = 0.0;     // Accumulator

      // Accumulate the sum of the elements
      // in the rainfall array.
      for (int index = 0; index < rain.length; index++)
         //total += sales[index];
         total = total + rain[index];

      // Return the total.
      return total;
   }

   /**
      getAverage method
      @return The average of the elements
      in the rainfall array.
   */

   public static double averageRain(double[] rain)
   {
      return totalRain(rain) / rain.length;
   }

   /**
      getHighest method
      @return The highest value stored
      in the rainfall array.
   */

   public static double mostRain(double[] rain)
   {
      double highest = rain[0];

      for (int index = 1; index < rain.length; index++)
      {
         if (rain[index] > highest)
            highest = rain[index];
      }

      return highest;
   }

   /**
      getLowest method
      @returns The lowest value stored
      in the rainfall array.
   */

   public static double leastRain(double[] rain)
   {
      double lowest = rain[0];

      for (int index = 1; index < rain.length; index++)
      {
         if (rain[index] < lowest)
            lowest = rain[index];
      }

      return lowest;
   }
}

Answer 1

这是一个使用JAVA 8 Streams的非常简单的方法：

Double[] doubles = new Double[12];


       List<Double> doubleList = Arrays.asList(doubles);


       Double max = doubleList.stream().mapToDouble(dub -> dub).max().getAsDouble();

       Double min = doubleList.stream().mapToDouble(dub -> dub).min().getAsDouble();

Answer 2

试试这个：不是指定索引的下雨量，而是想要索引istelf。

public static double mostRain(double[] rain)
   {
      double highest = rain[0];
      int highestMonth = 0;

      for (int index = 1; index < rain.length; index++)
      {
         if (rain[index] > highest)
            highest = rain[index];
            highestMonth = index;
      }

      return highestMonth;
   }

如何打印数组的最大值和最小值？

2 个答案: