是否可以/合法地进行跨队列依赖操作?
考虑以下内容......
let operationA = NSBlockOperation(block: someBlock)
let operationB = NSBlockOperation(block: someOtherBlock)
let operationC = NSBlockOperation(block: finalBlock)
operationC.addDependency(operationA)
operationC.addDependency(operationB)
OperationQueue().addOperation(operationC)
OperationQueue().addOperation(operationA)
OperationQueue().addOperation(operationB)
我在文档中的任何地方都没有看到这是一种限制用法,但我也不确定这样的事情是否可行/支持。 (注意:我也不是说这是不是很好的做法。只是试着用语言来看看什么可能作为思考的食物。)
答案 0 :(得分:1)
是
"关于依赖关系的另一个好处是它们不受操作队列的限制。现在,我的意思是什么?如果应用程序中有两个操作队列,则第一个队列中的操作可能取决于第二个队列中的操作。"
https://developer.apple.com/videos/play/wwdc2015/226/
以下是您可以尝试的示例:
NSOperationQueue *queue1 = [[NSOperationQueue alloc] init];
NSBlockOperation *a1 = [[NSBlockOperation alloc] init];
NSBlockOperation *a2 = [[NSBlockOperation alloc] init];
[a1 addExecutionBlock:^{
NSLog(@"a1");
NSOperationQueue *queue2 = [[NSOperationQueue alloc] init];
NSBlockOperation *b1 = [[NSBlockOperation alloc] init];
NSBlockOperation *b2 = [[NSBlockOperation alloc] init];
[b1 addExecutionBlock:^{
NSLog(@"b1");
}];
[b2 addExecutionBlock:^{
NSLog(@"b2");
}];
[a2 addDependency:b2]; // makes this inner queue finish first
[b2 addDependency:b1];
[queue2 addOperations:@[b1, b2] waitUntilFinished:NO];
}];
[a2 addExecutionBlock:^{
NSLog(@"a2");
}];
[a2 addDependency:a1];
[queue1 addOperations:@[a1, a2] waitUntilFinished:NO];
输出:
2017-01-08 00:27:03.019497 OpTest[26141:36238589] a1
2017-01-08 00:27:03.019621 OpTest[26141:36238621] b1
2017-01-08 00:27:03.019721 OpTest[26141:36238589] b2
2017-01-08 00:27:03.019773 OpTest[26141:36238621] a2
如您所见,[a2 addDependency:b2]
行允许操作的子队列在主队列中完成。