如何让用户在python中的passowrd程序上退出程序

Question

请有人试着帮我解决这个问题。因此，一旦用户猜到整个程序关闭3次，但一旦用户弄错了，它就不会让他们退出程序。是的，我知道我再次提出同样的问题，但我还没有回答我的问题，所以请有人帮忙。

这是另一个我尝试过的人。如果用户通过尝试猜测密码错误而获得一定数量的尝试，则有关如何退出程序的任何建议。我一直在尝试使用sys.exit和exit（），但它还没有为我工作，所以也许你可以尝试一下，（但请记住我的老师想要它，以便 IDLE ）。

Counter=1
Password=("Test")
Password=input("Enter Password: ")
if Password == "Test":
    print("Successful Login")
    while Password != "Test":
        Password=input("Enter Password: ")
        Counter=Counter+1
        if Counter == 3:
            print("Locked Out: ")
break

Answer 1

counter = 1
password = input("Enter password: ")
while True:
    if counter == 3:
        print("Locked out")
        exit()
    elif password == "Test":
        print("That is the correct password!")
        break
    else:
        password = input("Wrong password, try again: ")
    counter += 1

Answer 2

您需要在while循环中移动条件counter==3

这也可以这种方式完成

import sys
password = input("Enter password : ")
for __ in range(2):     # loop thrice
    if (password=="Test"):
        break           #user has enterd correct password so break
    password = input("Incorrect, try again : ")
else:
    print ("Locked out")
    sys.exit(1)

#You can put your normal code that is supposed to be
# executed after the correct password is entered
print ("Correct password is entered :)")
#Do whatever you want here

更好的方法是将此密码检查事物包装到函数中。

import sys
def checkPassword():
    password = input("Enter password : ")
    for __ in range(2):
        if (password=="Test"):
            return True
        password = input("Incorrect, try again : ")
    else:
        print ("Locked out")
        return False

if (checkPassword()):
    #continue doing you main thing
    print ("Correct password entered successfully")

Answer 3

将计数器检查移至while循环。

还可以使用getpass在python中输入密码：）

import sys
import getpass

counter = 1
password = getpass.getpass("Enter Password: ")
while password != "Test":
  counter = counter + 1
  password = getpass.getpass("Incorrect, try again: ")
  if counter == 3:
    print("Locked Out")
    sys.exit(1)
print("Logged on!")