我正在尝试使用JOIN和RAND
进行更新UPDATE table1 a INNER JOIN table2 b USING(id)
SET a.description = CONCAT('different words', b.name)
WHERE a.description LIKE ''
ORDER BY RAND() LIMIT 100;
我收到错误:UPDATE和ORDER BY的使用不正确
没有加入以下代码完美无缺
UPDATE table1 SET description = CONCAT('different words', name)
WHERE description LIKE ''
ORDER BY RAND() LIMIT 100;
感谢您的帮助
答案 0 :(得分:0)
假设您正在使用String BId = "button1"; // for example
int id = getResources().getIdentifier(BId, "id", getPackageName());
// finds R.id.button1
bdatum0 = (Button) findViewById(id);
,您应该将您的查询(使用用户变量和order by)包装为内联视图(MySQL将其称为派生表)。在UPDATE语句中将整个视图引用为行源。所以你的查询应该是这样的:
mysql
答案 1 :(得分:0)
试试这个:
UPDATE a
SET a.description = CONCAT('different words', b.name)
FROM table1 a
INNER JOIN table2 b ON a.id=b.id
WHERE a.description LIKE ''
ORDER BY RAND() LIMIT 100;