Question

这就是我想要输出的内容：

Choose an option :

(1) Water

(2) Soda pop

(3) Beer

?-> Enter an option number :

这是我的代码：

public class Menu 
{   

    private String[] optionList;

    private String openingMessage;

    private String topPrompt;

    private String closingMessage;

    private String bottomPrompt;


    public Menu(String[] options)
    {
        optionList = options;
        openingMessage = "";
        topPrompt = "Choose an option:";
        closingMessage = "";
        bottomPrompt = "Enter an option number:";
    }

    public Menu()
    {
        optionList = null;
        openingMessage = "";
        topPrompt = "";
        closingMessage = "";
        bottomPrompt = "";
    }

    public boolean isEmpty(String[] options)
    {
        if (options == null)
        {
            return true;
        }

        return false;
    }

    public int length(String[] options)
    {
        return options.length;
    }

    public String toString()
    {       
        return (topPrompt + "\n" + "?->" + " " + bottomPrompt);
    }

    public static void main(String[] args) 
    {
        String[] drink_options = {"Water", "Soda pop", "Beer"};

        Menu drinkMenu = new Menu(drink_options);

        System.out.println(drinkMenu);
        //System.out.println(drinkMenu.isEmpty(drink_options));
        //System.out.println(drinkMenu.length(drink_options));
    }

我需要在toString()方法中做些什么才能让括号中的数字出现在String数组元素的每个列表之前？我想我可以使用length()方法获取数组中元素的数量n，并使用for循环在前面添加数字。

请告诉我您的见解。

谢谢！

Answer 1

尝试类似：

public boolean isEmpty()
{
    return options == null || options.length == 0
}

public int length()
{
    return isEmpty() ? 0 : options.length;
}

public String toString()
{       
    String result = topPrompt + "\n";
    for (i=0; i<lenth(); i++) {
         result += "(" + (i+1)+ ") " + options[i]; 
    }
    result  += "?->" + " " + bottomPrompt);
    return result;
}

使用toString（）方法打印String Array对象的编号列表

1 个答案: