这是我尝试使用的js代码。我不喜欢同样的代码再次重复,我无法帮助自己以更好的方式做到这一点。
$(function(){
$('[data-behavior~=quick-reject]').on("click", function(){
var form = $(this).closest("[data-behavior~=modal-footer]").find("form");
var some_action = form.find("#some_actions").val();
var some_reasons = form.find("[data-behavior~=escalation-reason-select-box]");
if((some_reasons.val() === "") && ( some_action === "reject")){
var errorReason = "Please select a reason";
form.addClass("error").
parent().
find("div.error").
html(errorReason);
}else{
form.submit();
}
});
$(document).on("change", "#some_actions", function (){
var form = $(this).closest("[data-behavior~=modal-footer]").find("form");
var some_action = form.find("#some_actions").val();
var some_reasons = form.find("[data-behavior~=escalation-reason-select-box]");
if(some_action === "verify"){
some_reasons.hide();
}else{
some_reasons.show();
}
});
});
答案 0 :(得分:0)
你可以制作一个小实用功能,比如。
function getVars(that) {
var form = $(that).closest("[data-behavior~=modal-footer]").find("form");
return {
form: form,
some_action: form.find("#some_actions").val(),
some_reasons: form.find("[data-behavior~=escalation-reason-select-box]")
}
}
$('[data-behavior~=quick-reject]').on("click", function(){
var v = getVars(this);
if((v.some_reasons.val() === "") && ( v.some_action === "reject")){
var errorReason = "Please select a reason";
v.form.addClass("error").
parent().
find("div.error").
html(errorReason);
}else{
v.form.submit();
}
});
$(document).on("change", "#some_actions", function (){
var v = getVars(this);
if(v.some_action === "verify"){
v.some_reasons.hide();
}else{
v.some_reasons.show();
}
});