SELECT m.id
,owner.id AS msg_owner
,owner.name AS msg_owner_name
,m.sender_user_id
,sender.name AS sender_name
,m.recipient_user_id
,recipient.name AS recipient_name
,m.body AS msg_body
,m.created_at
FROM messages m
INNER JOIN users sender
ON sender.id = m.sender_user_id
INNER JOIN users recipient
ON recipient.id = m.recipient_user_id
INNER JOIN users owner
ON owner.id = m.user_id
代码编译,工作,它执行lambda函数的更改,但是假设我想找出foo的确切返回类型。是int,void,bool等吗?我有办法表达它或其他什么吗?