首先,我制作了一个简单的代码,用于检查2条线是否根据x和y坐标给出的4个点发生碰撞。它检查两条线的角度(我的代码中的变量k)是否相同,在这种情况下它们是平行的,否则它们会发生碰撞。角度(k)基于数学方程Click here [k =(y2-y1)/(x2-x1)]计算。现在我不知道如何得到他们碰撞的重点。如果你能帮助我,我将非常感激。提前谢谢。
我的代码:(我打电话来计算角度)
static void MetodaTrazenjaPresjeka(Duzina d1, Duzina d2)
{
int k11 = d1.Krajy - d1.Pocy; //y2-y1 - first line
int k12 = d1.Krajx - d1.Pocx; //x2-x1 - first line
double k1 = (double)k11 / k12; //angle of the first line
int k21 = d2.Krajy - d2.Pocy; //y2-y1 - second line
int k22 = d2.Krajx - d2.Pocx; //x2-x1 - second line
double k2 = (double)k21 / k22; //angle of the second line
if (k1 == k2)
{
//they are parallel
Console.WriteLine("MOJA METODA:");
Console.WriteLine("-----------------------------------");
Console.Write("Pravci zadani tockama su paralelni!");
}
else
{
//lines are colliding
Console.WriteLine("MOJA METODA:");
Console.WriteLine("-----------------------------------");
Console.Write("Pravci zadani tockama se sijeku!");
}
}
Duzina班的代码:
class Duzina
{
private int pocx, pocy, krajx, krajy;
//read/write attribute for the x coordinate of the first point
public int Pocx
{
get { return pocx; }
set { pocx = value; }
}
//read/write attribute for the y coordinate of the first point
public int Pocy
{
get { return pocy; }
set { pocy = value; }
}
//read/write attribute for the x coordinate of the second point
public int Krajx
{
get { return krajx; }
set { krajx = value; }
}
//read/write attribute for the y coordinate of the second point
public int Krajy
{
get { return krajy; }
set { krajy = value; }
}
//method that will print out coordinates of the given points
public void Ispis()
{
Console.Write("Pocetna tocka: ({0},{1})",Pocx,Pocy);
Console.Write("Krajnja tocka: ({0},{1})", Krajx, Krajy);
}
}
答案 0 :(得分:0)
线方程:(?<==)[\w.]++
y = m * x + b
现在将从4)获得的 intersect.x 插回到2)中的任一等式中以获得 intersection.y