Datadriven shell编程?建议,请

时间:2016-11-24 09:56:06

标签: shell data-driven

我想将我的shell脚本转换为使用datadriven方法。但是由于在任何shell中都没有“表”类型值(我知道),建议的替代方法是什么?

我正在寻找的解决方案可以让人们做以下事情:

animals = [['horse', 300 'brown'],
           ['cat', 3, 'black'],
           ['elephant', 3000, 'grey'],
           ['mouse', 0.3, 'grey']]
for a in animals ; do
  echo "A typical $a[1] is $a[3] and weighs about $a[2] kilograms."
done

更准确地说,我想尝试一些命令并查看其中一个命令是否可用,然后向其发送参数:

commands = [['c1', '-m', '-i'],
            ['c2', '-message', '-icon'],
            ['c3', '/m', '/i']]
for c in commands ; do
  if exists c[1] ; then
    command = c[1]
    message_option = c[2]
    icon_option = c[3]
    break;
  fi
done
$command $message_option "message" $icon_option icon

3 个答案:

答案 0 :(得分:4)

不需要玄武。这可以通过while read循环读取 here-document 来巧妙地解决:

#!/bin/sh
while read animal weigth colour; do
  printf '%s\n' "A typical $animal is $colour and weighs about $weight kilos."
done << EOF
horse 300 brown
cat 3 black
elephant 3000 grey
mouse 0.3 grey
EOF

观察这是如何通过名称引用元素,而不是使用1,2,3进行神秘索引。它不会分叉/执行任何外部命令并击败循环体中的3个awk,在另一个答案中看到

答案 1 :(得分:2)

您可以根据您的要求在bash中定义和使用associative-arrays

#!/bin/bash

# declaring the Associative array
declare -a animals

animals[0]="'horse':300:'brown'"
animals[1]="'cat':3:'black'"
animals[2]="'elephant':3000:'grey'"
animals[3]="'mouse':0.3:'grey'"

for animal in "${animals[@]}"
do
    myArray=(${animal//:/ })
    printf "A typical "${myArray[0]}" is "${myArray[2]}" and weighs about "${myArray[1]}" kilograms.\n"
done

上面唯一棘手的部分是parameter-expansion类型

${parameter/pattern/string}
          The pattern is expanded to produce a pattern just as in filename expansion. Parameter is expanded and the longest match of pattern against its value is replaced with string. 
If pattern begins with ‘/’, all matches of pattern are replaced with string. Normally only the first match is replaced. 

理想情况下,字符串'horse':300:'brown'被拆分为单个元素并存储在数组myArray中,后来用于访问C风格循环中的各个元素。

答案 2 :(得分:0)

试试这个?

cat file
'horse', 300, 'brown'
'cat', 3, 'black'
'elephant', 3000, 'grey'
'mouse', 0.3, 'grey'

for i in {1..4} ; 
do 
    animal=$(awk -F, -v var="$i" 'NR== var {print $1}' file) 
    weight=$(awk -F, -v var="$i" 'NR== var {print $2}' file) 
    colour=$(awk -F, -v var="$i" 'NR== var {print $3}' file) 
    echo "A typical "$animal" is "$colour" and weighs about "$weight" kilos." 
done

输出 -

A typical 'horse' is 'brown' and weighs about  300 kilos.
A typical 'cat' is  'black' and weighs about  3 kilos.
A typical 'elephant' is  'grey' and weighs about  3000 kilos.
A typical 'mouse' is  'grey' and weighs about  0.3 kilos.