Question

我是一个菜鸟程序员，但我一直坚持这一点代码。你如何重新开始？我已经尝试了几种不同的方法，但它们都要么花费大量的代码，要么无法正常工作。我一直在尝试在我的所有编程任务中实现这段“简单”的代码，但它还没有成功。谢谢！

P.S。我已经完成了作业。我只是想让它更“完整”。

public class OddProduct {


    public static void main(String[] args) {
       //Inputs from user
       System.out.println("Enter an odd number");
       Scanner input_odd = new Scanner(System.in);
       int odd = input_odd.nextInt(); 

       int oddproduct = 1;

       //Multiplies all odd integers 
       for (int counter = 1; counter <= odd; counter = counter + 2){
            oddproduct = oddproduct * counter;
       }//end of for- loop 
       System.out.printf("\nThe product of all the odd integers up to %d is %d\n",
               odd, oddproduct);

       /* MY NOTES FOR RECURSE
       if (odd%2 == 1){ proceed normally} 
       else if (odd%2 != 1) { HOW TO LOOP BACK???}
       else { println = "Application closed"} 
       */
    }//end of main method

}//end of OddProduct class

Answer 1

根据您的备注，我认为这是您需要的

   Scanner input_odd = new Scanner(System.in);
   int odd = 0; 

   while (odd % 2 != 1) {  // fails first time && if user enters even number
       System.out.println("Enter an odd number");
       odd = input_odd.nextInt(); 
   }

如何回归开始？

1 个答案: