将Count（）转换为PHP中的多维数组

Question

如果我有这个数组：

Array (
    [0] => Array (
        [booking_id] => 1
        [booking_status] => confirmed
        [client_name] => Bale
        [client_firstname] => Gareth
        [days] => Array (
            [day_id] => 2016-11-23,2016-11-24
            [room_id] => 2
        )
    )
)

如何才能将商品数量转换为day_id？

Answer 1

$sum = 0;
foreach ($data as $booking) {
    $sum += sizeof(explode(",",$booking["days"]["day_id"]));
}

Answer 2

您可以使用array_reduce迭代数组项并获得最终结果。看看this：

function reduce_func($carry, $item){
    if (isset($item['days']) && !empty($item['days']['day_id'])){
        $carry += count(array_unique(array_filter(explode(',', $item['days']['day_id']))));
    }
    return $carry;
}

$result = array_reduce($arr, "reduce_func", 0);

<强>更新

请注意，您还可以向array_filter提供回调，以过滤掉您要计算的所需条目，例如。正则表达式检查每个条目是否为有效日期。这是PHP manual for array_filter。

Answer 3

$sum =0;
for ($count = 0; $count < count($data); $count++) {
    $booking = $data[$count];
    $day_ids = explode(",", $booking['days']['day_id'];
    $sum     = $sum + count($day_ids);
}