Question

我有这个数组：

Array ( [0] => Array ( [Num] => 2 ) [1] => Array ( [Num] => 3 ) [2] => Array ( [Num] => 13 ) [3] => Array ( [Num] => 2 ) [4] => Array ( [Num] => 3 ) [5] => Array ( [Num] => 3 ) [6] => Array ( [Num] => 1 ) [7] => Array ( [Num] => 44 ) )

我想得到重复值的数量，例如该数组有5个值重复。这个问题的简单方法??帮助我！

php代码：

$count = 0;
$temp = array();
for($i=0;$i<=sizeof($Num);$i++){
    for($j=$i+1;$j<=sizeof($Num);$j++){
        if($Num[$i]==$Num[$j]){
            $count++;
            $temp[]=$Num[$j];
        }
    }
}
var_dump($temp);
echo $count;

Answer 1

从PHP 5.5开始（因为array_column *）你可以使用

 Start proc com.**.** for activity com.**.**/com.**.**: pid=11091 uid=10146 gids={50146, 3003, 1028, 1015} by log Tag ActivityManager.

即。
- 获取所有元素＆＃39; Num＆＃39;在$ num中作为＆＃34;持平，1-d＆＃34;阵列。
- 计算每个值的出现次数 - 只在数组中保持count（）＆gt; 1

- *在用户提供的array_column备注中有php＆lt; 5.5
的填充内容而且由于$ num中每个数组只有一个元素，你也可以使用array_map / array_shift

编辑：没有array_column的更详细的版本

<?php
$num = array (
    array ( 'Num' => 2 ), array ( 'Num' => 3 ), array ( 'Num' => 13 ), array ( 'Num' => 2 ),
    array ( 'Num' => 3 ),   array ( 'Num' => 3 ),   array ( 'Num' => 1 ), array ( 'Num' => 44 ) 
);

$x = array_filter(
    array_count_values(
        array_column($num, 'Num')
    ),
    function($e) { return $e>1; }
);
var_export($x);

打印<?php $num = array ( array ( 'Num' => 2 ), array ( 'Num' => 3 ), array ( 'Num' => 13 ), array ( 'Num' => 2 ), array ( 'Num' => 3 ), array ( 'Num' => 3 ), array ( 'Num' => 1 ), array ( 'Num' => 44 ) ); // first remove the superfluous second dimension $num = array_map(function($e) { return $e['Num']; }, $num); // -> $num = [ 2,3,13,2,3,3,1,44] $num = array_count_values($num); // -> $num = [2=>2, 3=>3, 13=>1, 1=>1, 44=>1] $num = array_filter($num, function($e) { return $e>1; }); // -> $num = [2=>2, 3=>3] printf('There are %d duplicate values. A total of %d elements are doublets', count($num), array_sum($num) );

Answer 2

解决它没有花哨的东西，但它应该工作：

function carousel() {
  var timer, count = 0;
  var loop = function loop(count) {
    if (count === imgURLS.length) count = 0;
    image.src = imgURLS[count];
    timer = setTimeout(loop, 2000, ++count);
  }
  loop(count);
}

carousel();

Answer 3

for PHP 5＆gt; = 5.5.0，PHP 7

$Num = array ( 
        "0" => array ( 'Num' => 2 ),
        "1" => array ( 'Num' => 3 ), 
        "2" => array ( 'Num' => 13), 
        "3" => array ( 'Num' => 2 ), 
        "4" => array ( 'Num' => 3 ), 
        "5" => array ( 'Num' => 3 ), 
        "6" => array ( 'Num' => 1 ), 
        "7" => array ( 'Num' => 44 ) );

$subArr = array_column($Num, 'Num');
$countArr = array_count_values($subArr);//array with all count
$filteredArr = array_filter($countArr, function ($val) {return $val > 1;});//filter that is having duplicates
echo "Count of Duplicate : ".array_sum($filteredArr);

否则

$Num = array ( 
        "0" => array ( 'Num' => 2 ),
        "1" => array ( 'Num' => 3 ), 
        "2" => array ( 'Num' => 13), 
        "3" => array ( 'Num' => 2 ), 
        "4" => array ( 'Num' => 3 ), 
        "5" => array ( 'Num' => 3 ), 
        "6" => array ( 'Num' => 1 ), 
        "7" => array ( 'Num' => 44 ) );
$countArr = array();
foreach ($Num AS $eachArr) {
    $countArr[$eachArr['Num']] += 1;
}

$filteredArr = array_filter($countArr, function ($val) {return $val > 1;});//filter that is having duplicates
echo "Count of Duplicate : ".array_sum($filteredArr);

数组php中重复值的计数

3 个答案: