Question

我正在尝试从codeacademy的课程开始自学Python，到目前为止，它一直没问题。然而，我在学生成为老师7/9遇到了障碍。我无法找到讨论此问题的帖子，但如果我错过了一个，请随时告诉我。

根据codeacademy我成功完成了这个练习，但我知道这个代码有问题。当我在repl.it中使用下面的代码时，get_average（student）会返回正确的值。我已经通过改变成绩来测试这一点，但确保 - 但get_letter_grade（得分）为每个学生返回“A”。我尝试使用允许的数字范围更具体（见下文），但我仍然遇到同样的问题。

lloyd = {
        "name": "Lloyd",
        "homework": [90.0, 97.0, 75.0, 92.0],
        "quizzes": [88.0, 40.0, 94.0],
        "tests": [75.0, 90.0]
    }
alice = {
        "name": "Alice",
        "homework": [100.0, 92.0, 98.0, 100.0],
        "quizzes": [82.0, 83.0, 91.0],
        "tests": [89.0, 97.0]
    }
tyler = {
        "name": "Tyler",
        "homework": [0.0, 87.0, 75.0, 22.0],
        "quizzes": [0.0, 75.0, 78.0],
        "tests": [100.0, 100.0]
    }

def average(numbers):
        total = sum(numbers)
        total = float(total)/len(numbers)
        return total

def get_average(student):
        homework = average(student["homework"])
        quizzes = average(student["quizzes"])
        tests = average(student["tests"])
        studentaverage = (homework * .1 + quizzes * .3 + tests *.6)
        return studentaverage

def get_letter_grade(score):
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"

我还尝试稍微更改get_letter_grade（得分）功能以使其更具体/受限制（我可能会采用错误的方式;我对此非常陌生），如下所示：

def get_letter_grade(score):
        if score >= 90:
            return "A"
        elif score >= 80 and score < 90:
            return "B"
        elif score >= 70 and score < 80:
            return "C"
        elif score >= 60 and score < 70:
            return "D"
        else:
          return "F"

但如上所述，我有同样的问题：无论我如何改变他们的成绩，它都会为每个学生返回“A”。

非常感谢您分享的任何建议，见解，智慧等等！

谢谢！

Answer 1

我尝试了上面的代码，它完全正常，没有任何更改。也许如果你可以分享你调用函数的方式，我可以对你可能遵循的错误程序有所了解。下面附有代码的片段及其相应的输出。

lloyd = {
        "name": "Lloyd",
        "homework": [90.0, 97.0, 75.0, 92.0],
        "quizzes": [88.0, 40.0, 94.0],
        "tests": [75.0, 90.0]
    }
alice = {
        "name": "Alice",
        "homework": [100.0, 92.0, 98.0, 100.0],
        "quizzes": [82.0, 83.0, 91.0],
        "tests": [89.0, 97.0]
    }
tyler = {
        "name": "Tyler",
        "homework": [0.0, 87.0, 75.0, 22.0],
        "quizzes": [0.0, 75.0, 78.0],
        "tests": [100.0, 100.0]
    }

def average(numbers):
        total = sum(numbers)
        total = float(total)/len(numbers)
        return total

def get_average(student):
        homework = average(student["homework"])
        quizzes = average(student["quizzes"])
        tests = average(student["tests"])
        studentaverage = (homework * .1 + quizzes * .3 + tests *.6)
        return studentaverage

def get_letter_grade(score):
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"

# To calculate the grades of each student
grade_tyler = get_letter_grade(get_average(tyler))
grade_lloyd = get_letter_grade(get_average(lloyd))
grade_alice = get_letter_grade(get_average(alice))

print(grade_lloyd)
print(grade_alice)
print(grade_tyler)

输出：

乙

A

C

此外，我还尝试单独调用方法，结果与预期一致。

grade_A = get_letter_grade(95)
grade_B = get_letter_grade(85)
grade_C = get_letter_grade(75)
grade_D = get_letter_grade(65)

print(grade_A)
print(grade_B)
print(grade_C)
print(grade_D)

输出：

A

乙

C

d

python codeacademy发信

1 个答案: