Codecademy：平均值

Question

我正在从Code Academy处理这个问题，我想要的代码是分别返回每个学生的测试，测验和家庭作业平均值。

这就是我现在的代码。

它说错误消息'无效语法'等等。

lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]

def average(some):
    return sum(some)/len(some)

students = [lloyd, alice, tyler]
def get_class_average(students):
    for student in students:
         total += get_average(student)
    return float(total) / len(students)

Answer 1

你用词典而不是列表来调用get_average()（我假设你的意思是average()）。因此sum()无法使用它。为了获得实际的家庭作业或测验或测试列表，您必须total += get_average(student['homework'])。

你的tyler字典之后你也错过了}。这将使python认为def average位是字典的一部分，但它不能，因此错误。

Answer 2

看来你错过了

之前的卷曲

def average...

应该是

tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}
def average ...

同样在get_average_class中，您没有说明get_average是什么。我认为它是使用你省略的average的东西，但如果你的意思是平均而不是你有问题。

Answer 3

lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}
def average(some):
    return sum(some)/len(some)

students = [lloyd, alice, tyler]
def get_class_average(students):
    for student in students:
         total += get_average(student)
    return float(total) / len(students)

Answer 4

您忘了在average功能之前关闭大括号。