计算这个星期的日期范围

Question

我希望找出是否有办法计算这周的日期范围。

例如

Monday -    2016-11-21
Tuesday -   2016-11-22
Wednesday - 2016-11-23

依此类推。

如果有人可以帮我解决那些很棒的语法和计算方法。

Answer 1

如果您在自己的专栏中对他们感到满意，那么您可以做这样的事情;

SELECT
DATEADD(wk, DATEDIFF(wk, 6, GETDATE()), 0) Last_Monday
,DATEADD(WEEK, DATEDIFF(WEEK, 2, GETDATE()) - 1, 1) Last_Tuesday
,DATEADD(WEEK, DATEDIFF(WEEK, 2, GETDATE()) - 1, 2) Last_Wednesday
,DATEADD(WEEK, DATEDIFF(WEEK, 2, GETDATE()) - 1, 3) Last_Thursday

结果;

Last_Monday             Last_Tuesday            Last_Wednesday          Last_Thursday
2016-11-14 00:00:00.000 2016-11-15 00:00:00.000 2016-11-16 00:00:00.000 2016-11-17 00:00:00.000

如果你需要行，那么只需结合结果;

SELECT DATEADD(wk, DATEDIFF(wk, 6, GETDATE()), 0) Date_Field, 'Last_Monday' Day_Name
UNION
SELECT DATEADD(WEEK, DATEDIFF(WEEK, 2, GETDATE()) - 1, 1), 'Last_Tuesday'
UNION
SELECT DATEADD(WEEK, DATEDIFF(WEEK, 2, GETDATE()) - 1, 2), 'Last_Wednesday'
UNION 
SELECT DATEADD(WEEK, DATEDIFF(WEEK, 2, GETDATE()) - 1, 3), 'Last_Thursday'

结果;

Date_Field                  Day_Name
2016-11-14 00:00:00.000     Last_Monday
2016-11-15 00:00:00.000     Last_Tuesday
2016-11-16 00:00:00.000     Last_Wednesday
2016-11-17 00:00:00.000     Last_Thursday

请阅读此处以获得有关其工作原理的详细说明;

DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0) Can someone explain me this

Answer 2

DECLARE @StartDT DATE = '2016-11-21'

;WITH CTE (_Date)
AS (
    SELECT @StartDT

    UNION ALL

    SELECT DATEADD(DAY, 1, _Date)
    FROM CTE
    WHERE _Date < DATEADD(DAY, 6, @StartDT)
    )
SELECT _Date
    ,DATENAME(W, _Date)
FROM CTE

Answer 3

您可以设置一周的开始和结束日期，并通过这些日期进行迭代：

Declare @startDay   datetime,
        @endDay     datetime,
        @iterDate   datetime

Set @startDay = dateadd(day, datediff(day, 0, getdate()) / 7 * 7, 0) --Starting day of this week
Set @endDay = dateadd(day, 7, @startDay)

Set @iterDate = @startDay

Declare @tmpResults Table (Date datetime, DayName varchar(20))

While (@iterDate < @endDay)

Begin
    Insert into @tmpResults (Date, DayName)
    Values (@iterDate, datename(weekday, @iterDate))

    Set @iterDate = dateadd(day, 1, @iterDate)
End

select Date, DayName From @tmpResults

结果：