输出始终为X.

时间:2016-11-22 21:51:00

标签: system-verilog state-machine

每当我为我的systemverilog代码编写一个测试平台时,即使实现是正确的,输出似乎总是为X.我的错误在哪里?

`timescale 1ns / 1ps

module fsm( input logic clk, input logic reset, 

input logic start, clockwise,
output logic [3:0] pattern);
parameter      A=4'b1100,
               B=4'b0110,
               Ab=4'b0011,
               Bb=4'b1001;
typedef enum logic [1:0] {S0,S1,S2,S3} statetype;

statetype state, nextstate;

//state register
always@ (posedge clk)
begin
if (reset)
    state= S0;
else 
    state = nextstate;
end
//nextstate logic
always_comb
    case(state)
    S0: if(start==1 && clockwise==0)
            nextstate<= S3;
        else if(start==1&&clockwise==1)
            nextstate<=S1;
        else 
            nextstate<=S0;
    S1: if(start==1 && clockwise==0)
            nextstate<= S0;
        else if(start==1&&clockwise==1)
            nextstate<=S2;
        else 
            nextstate<=S1;
    S2: if(start==1 && clockwise==0)
            nextstate<= S1;
        else if(start==1&&clockwise==1)
             nextstate<=S3;
        else 
             nextstate<=S2;
    S3: if(start==1 && clockwise==0)
             nextstate<= S2;
        else if(start==1&&clockwise==1)
             nextstate<=S0;
        else 
             nextstate<=S3;
    endcase
//output logic
always@ (posedge clk)
    case(state)
       S0: pattern= A;
       S1: pattern= B;
       S2: pattern= Ab;
       S3: pattern= Bb;
    endcase
endmodule

这是我的测试平台

module fsmtest();
logic clk, reset, clockwise, start;
logic [3:0] pattern;
fsm dut(clk, reset, start, clockwise, pattern);
//generate clock
always
    begin
        clk=0; #5; clk=1; #5;
    end
initial
    begin
        reset=0;
        start=1;
        clockwise=1;
        #10;
        start=0;
        #10;
    end
endmodule 

我不确定这是我的有限状态机是错误还是它是测试平台。希望得到一些帮助,提前谢谢。

1 个答案:

答案 0 :(得分:3)

您从未断言重置,因此您的状态机仍然未初始化。您应该通过在case语句中添加default分支来解决此问题。然后,如果您的DUT处于未编码状态,则可以保证进入已知状态。